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vampirchik [111]
3 years ago
12

Which ratio is equivalent to 12 over 14

Mathematics
2 answers:
Alecsey [184]3 years ago
5 0
12/14=6/7

Because you divide by 2. 
kaheart [24]3 years ago
5 0
6/7, you simplify it by diving by 2
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Suppose a simple random sample of size n = 14 is obtained from a population with μ = 61 and σ = 17.
sergejj [24]

Answer:

C. The population must be normally distributed.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For us to apply the central limit theorem with a sample size of 14, the underlying population must be normally distributed.

So the correct answer is:

C. The population must be normally distributed.

5 0
3 years ago
What is the probability of a coin being tossed 7 times and landing on all heads?
mote1985 [20]
A tree diagram can be drawn for a clearer understanding. The branches of the tails can be ignored since we are not concerned about that. To find the probability along the branches, we just have to multiply the probabilities of each branch, giving you an answer of 1/128

4 0
3 years ago
Could anyone help me with this ASAP ?
Ahat [919]

Answer:

Step-by-step explanation:

-3x^4 -9x^3+ 15x^2

-3x^2 ( x^2 + 3x -5)

if you use quadratic formula (see image)

~~~~~~~~~~~~~~~~~~~~~~

10x^3  -35x^2 +6x -21

5x2(2x-7) +3(2x-7)

(5x^{2} + 3) (2x-7)

3 0
3 years ago
Read 2 more answers
Consider rolling two fair dice one 3-sided the other 5-sided
Ne4ueva [31]

Since the dice are fair and the rolling are independent, each single outcome has probability 1/15. Every time we choose

1\leq x\leq 3,\quad 1\leq y \leq 5

We have P(X=x)=\frac{1}{3} and P(Y=y)=\frac{1}{5}, because the dice are fair.

Now we use the assumption of independence to claim that

P(X=x, Y=y) = P(X=x)\cdot P(Y=y) =\dfrac{1}{3}\cdot\dfrac{1}{5} = \dfrac{1}{15}

Now, we simply have to count in how many ways we can obtain every possible outcome for the sum. Consider the attached table: we can see that we can obtain:

  • 2 in a unique way (1+1)
  • 3 in two possible ways (1+2, 2+1)
  • 4 in three possible ways
  • 5 in three possible ways
  • 6 in three possible ways
  • 7 in two possible ways
  • 8 in a unique way

This implies that the probabilities of the outcomes of W=X+Y are the number of possible ways divided by 15: we can obtain 2 and 8 with probability 1/15, 3 and 7 with probability 2/15, and 4, 5 and 6 with probabilities 3/15=1/5

8 0
3 years ago
How do I find the ratio of this? It makes no sense to me
Volgvan

Answer:

\frac{169}{289}

Step-by-step explanation:

Given 2 similar figures with ratio of sides = a : b, then

ratio of areas = a² : b²

Here ratio of sides = 52 : 68 = 13 : 17 ← in simplest form, thus

ratio of areas = 13² : 17² = 169 : 289 = \frac{169}{289}

5 0
3 years ago
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