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allsm [11]
3 years ago
13

13) The graph

Mathematics
1 answer:
Sever21 [200]3 years ago
3 0

Hi there! g(0) means the value of g(x) at x = 0. Look at x = 0 and see which y-point makes x = 0.

See that y = 4 makes x = 0 for the graph. Thus, g(0) = 4.

Next is to find the domain and range. Domain is the set of all x-values while Range is the set of all y-values.

For domain, look at the horizontal x-axis plane and the graph. Notice how the graph infinitely goes up for both negative and positive. Since the graph is in negative and positive as well. That means the domain is all real numbers

For range, look at the vertical y-axis and the graph. Notice how when y < -2, there are no points that are part of the graph. The graph goes infinitely for range as well but there're no y-values less than -2 for the graph.

Therefore, range is y >= -2.

Answer

  • g(0) = 4
  • domain is set of all real numbers.
  • range is y >= -2
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<em>Camera 2nd has to cover the maximum angle, i.e. </em>78.70^\circ.

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle \triangle ABC with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles \angle A, \angle B, \angle C

As per Law of cosine:

cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}

Putting the values of a,b and c to find out angles \angle A, \angle B, \angle C.

cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ

cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ

cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ

<em>Camera 2nd has to cover the maximum angle</em>, i.e. 78.70^\circ.

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4 years ago
What is the sequence rule for : 1.8, 2.58, 3.90, 4.95, 6
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I believe there is a typo in the problem. It should be:<span>1.8, 2.85, 3.90, 4.95, 6
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