Answer:
![1)\ z=120\\\\2)\ g=46\\\\3)\ d=108\\\\4)\ r=39](https://tex.z-dn.net/?f=1%29%5C%20z%3D120%5C%5C%5C%5C2%29%5C%20g%3D46%5C%5C%5C%5C3%29%5C%20d%3D108%5C%5C%5C%5C4%29%5C%20r%3D39)
Step-by-step explanation:
1) Given the equation:
![z\div12=10](https://tex.z-dn.net/?f=z%5Cdiv12%3D10)
You can rewrite it in the following form:
![\frac{z}{12}=10](https://tex.z-dn.net/?f=%5Cfrac%7Bz%7D%7B12%7D%3D10)
You must solve for "z". To do it, you can multiply both sides of the equation by 12.
Then you get this solution:
![(12)(\frac{z}{12})=(10)(12)\\\\z=120](https://tex.z-dn.net/?f=%2812%29%28%5Cfrac%7Bz%7D%7B12%7D%29%3D%2810%29%2812%29%5C%5C%5C%5Cz%3D120)
2) The equation given is:
![5g=230](https://tex.z-dn.net/?f=5g%3D230)
Now, in order to solve for the variable "g", you can divide both sides of the equation by 5.
Then you get the following result:
![\frac{5g}{5}=\frac{230}{5}\\\\g=46](https://tex.z-dn.net/?f=%5Cfrac%7B5g%7D%7B5%7D%3D%5Cfrac%7B230%7D%7B5%7D%5C%5C%5C%5Cg%3D46)
3) Given the equation:
![d-21=87](https://tex.z-dn.net/?f=d-21%3D87)
You can solve for "d" adding 21 to both sides of the equation.
So the value of "d" is:
![d-21+21=87+21\\\\d=108](https://tex.z-dn.net/?f=d-21%2B21%3D87%2B21%5C%5C%5C%5Cd%3D108)
4) Having this equation:
![r + 35 = 74](https://tex.z-dn.net/?f=r%20%2B%2035%20%3D%2074)
You must subtract 35 from both sides of the equation in order to find the value of the variable "r".
This is:
![r + 35-35 = 74-35\\\\r=39](https://tex.z-dn.net/?f=r%20%2B%2035-35%20%3D%2074-35%5C%5C%5C%5Cr%3D39)