Answer:
y ≤ 3x - 2 and 4x + y ≥2
Step-by-step explanation:
We can easily solve this problem by using a plotting tool or any graphing calculator.
We test each case, until we arrive to the correct option
Case 1
y ≤ 3x - 2 and 4x + y ≥2
Correct Option.
Please see attached image for graph
Answer:
250%
Step-by-step explanation:
Answer:
The speed of plane against wind S 1 = 1020 kmph And
The speed of plane with wind S 2 = 1260 kmph
Step-by-step explanation:
Given as :
The distance of airplane against the wind = D 1 = 3060 km
The time taken in against the wind = T 1 = 3 hours
The distance of airplane with the wind = D 2 = 7560 km
The time taken in with the wind = T 2 = 6 hours
Now, Speed of plane against the wind = 
So, S 1 = 
Or, S 1 =
= 1020 kmph
Similarly
Speed of plane with the wind = 
Or, S 2 = 
Or, S 2 =
= 1260 kmph
Hence The speed of plane against wind S 1 = 1020 kmph And
The speed of plane with wind S 2 = 1260 kmph Answer
Answer:
19 m
Step-by-step explanation:
base=x
leg=3x-2
3x-2+3x-2+x=45
7x-4=45
7x=49
x=7
leg=3x+2=3(7)-2=19
Answer:
25 meters.
Step-by-step explanation:
Given in the question that,
Initial depth of the submarine = 8 meters
After the order of the captain, the submarine was made to dive another 17 meters.
So, the final cruising depth of the submarine can be calculated by <u>adding the initial depth of the submarine and the depth further increased upon the order of the captain</u>.
Thus, final cruising depth of the submarine = 8 + 17 = 25 meters.