3 less than the quotient of 20 and x, write an algebraic expression

A gardener is planting two types of trees:

denpristay [2]

It takes 12 years for both trees to be of same height

Solution:

Assume the year that it would take to these trees have the same height is : x (years)

Type A is 7 feet tall and grows at a rate of 23 inches per year:

Convert 7 feet to inches

We know that,

1 foot = 12 inch

7 feet = 12 x 7 inch = 84 inch

Thus, type A is 84 inches tall and grows at a rate of 23 inches per year

We can frame a equation as:

Type A = 84 + 23(number of years)

Type A = 84 + 23x ---------- eqn 1

Type B is 5 feet tall and grows at a rate of 25 inches per year

Convert 5 feet to inches

5 feet = 5 x 12 inches = 60 inches

Thus, type B is 60 inches tall and grows at a rate of 25 inches per year

We can frame a equation as:

Type B = 60 + 25(number of years)

Type B = 60 + 25x --------- eqn 2

For both the trees to be of same height, eqn 1 must be equal to eqn 2

84 + 23x = 60 + 25x

25x - 23x = 84 - 60

2x = 24

x = 12

Thus it takes 12 years for both trees to be of same height

7 0

3 years ago

Max saves up $6000.He elects to put it in a savings account that accrues 3.5% simple interest.How much money will he have in 6 y

Naddik [55]

$7200.. you would find out what 3.5% of $6000 (210) is and then multiply it by 6 (1200) and then add it to the original $6000

7 0

3 years ago

In your own words, what is a interquartile range? REWARDING BRAINLY

melisa1 [442]

Answer: The range of the medians of the numbers left and right of the median of the entire data set.

3 0

2 years ago

Read 2 more answers

What is the equation of this graph? coordinates: (1,7), (0,0),(-1,-7)

Vilka [71]

Answer:

y = 7x

Step-by-step explanation:

Slope: (7-0)/(1-0) = 7

y-intercept is obviously 0

y = 7x + 0

y = 7x

4 0

3 years ago

Read 2 more answers

A new car is purchased for 18000 dollars. The value of the car depreciates at 13.5% per year. What will the value of the car be,

leonid [27]

Answer:

The value of car after 14 years is $ 2,363.04

Step-by-step explanation:

Given as :

The price of new car = N = $ 18,000

The rate of depreciation of the value of the car = R = 13.5 % per year

Let The value of car after 14 years = $ x

The time period = 14 years

Now, According to question

The value of car after n years = initial value of car × $(1-\dfrac{\textrm rate}{100})^{\textrm Time}$

or, $ x = N × $(1-\dfrac{\textrm R}{100})^{\textrm n}$

or, $ x = $ 18,000 × $(1-\dfrac{\textrm 13.5}{100})^{\textrm 14}$

Or, $ x = $ 18,000 × $(0.865)^{14}$

∴ x = $ 18,000 × 0.13128

I.e x = $ 2,363.04

So, The value of car after 14 years = x = $ 2,363.04

Hence The value of car after 14 years is $ 2,363.04 Answer

8 0

2 years ago