Answer:
I can't see the side lengths so I can't answer it
Step-by-step explanation:
First, lets create a equation for our situation. Let

be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span>

<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is:

. So lets replace the values in our formula to find the average of our function:
![\frac{25(10)+100-[25(2)+100]}{10-2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B25%2810%29%2B100-%5B25%282%29%2B100%5D%7D%7B10-2%7D%20)



We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
Answer:
0.7 = 70%.
Step-by-step explanation:
There are 5 cans, and she will pick 2, so the number of possibilities that she can pick 2 cans is a combination of 5 choose 2:
C(5,2) = 5!(3!*2!) = 5*4/2 = 10
To find how many possibilities there are with at least 1 can of soup, we can find the number of groups that include no cans of soup, and then see how many possibilities complete the total 10:
There are 3 "no-soup" cans, so the number of possibilities is a combination of 3 choose 2:
C(3,2) = 3!/2! = 3
So, there are 3 possibilities that have no cans of soup, so the number of possibilities that have at least 1 can of soup is 10 - 3 = 7
Then, the probability is 7 / 10 = 0.7 = 70%.
Answer:
The answer is 900
Step-by-step explanation:
Hope this helps : )
Answer:
3/5=18/30
Step-by-step explanation:
3/5*6/6=18/30