Question

How do I solve this? 10 >= 7 + 3x and 9-4x =< 1

Answer 1

Answer:

No solution

Step-by-step explanation:

Solve each inequality separately

$10 \geq 7 + 3x$

Subtract 7 from both sides

$3 \geq 3x$

Divide both sides by 3

$1\geq x$

$x\leq 1$

Now solve the second inequality

$9-4x \leq 1$

Subtract 9 from both sides

$-4x \leq -8$

Divide both sides by -4.  when we divide by negative number then reverse the inequality sign.

$x\geq 2$

$x\leq 1$ and $x\geq 2$

There is no intersection of both inequalities

So , No solution

Answer 2

Subtract 7 on both side
Divide 3 from both sides
X should be >= to 1


Subtract 9 from both sides
Divide -4 from both sides
X should be =< 2