Answer:
39.17% probability that a woman in her 60s who has a positive test actually has breast cancer
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Positive test.
Event B: Having breast cancer.
3.65% of women in their 60s get breast cancer
This means that 
A mammogram can typically identify correctly 85% of cancer cases
This means that 
Probability of a positive test.
85% of 3.65% and 100-95 = 5% of 100-3.65 = 96.35%. So

What is the probability that a woman in her 60s who has a positive test actually has breast cancer?

39.17% probability that a woman in her 60s who has a positive test actually has breast cancer
That is permuations
that would be 10! or 10*9*8*7*6*5*4*3*2*1=3628800 ways
27.5 and 22.5 are the two numbers
Answer hey i dunno if you still need this but if you did could you translate to english
Answer:
65.93
Step-by-step explanation:
Okay, first lets convert the money.
100 ÷ 1.43 = 69.9300699301 (69.93)
69.93 - 4 = 65.93
Ashley has 65.93 pounds.
Hope this helps! Brainliest would be appreciated. :)