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Rasek [7]
3 years ago
11

: Find the slope between the two points given. Then, use the slope and point ONE to write the equation of the line in Point-Slop

e form. State the slope. Point One: (1,2) Point Two: (0,−1)
Mathematics
1 answer:
Ierofanga [76]3 years ago
8 0

Answer:

           slope:      \bold{m=3}

      equation:     \bold{y-2=3(x-1)}

Step-by-step explanation:

m=\dfrac{y_2-y_1}{x_2-x_1}\\\\(1,\,2)\ \implies\ x_1=1\,,\ y_1=2\\(0,\,-1)\ \implies\ x_2=0\,,\ y_2=-1\\\\m=\dfrac{-1-2}{0-1}=\dfrac{-3}{-1}=3

y-y_1=m(x-x_1)      - point-slope form of Equation of the Line

x_1=1\,,\ y_1=2\,,\ m=3\\\\equation:\\{}\qquad\qquad y-2=3(x-1)

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Find the missing y-coordinate that makes the two triangles congruent. Triangle ABC: A(8,4), B(2,6), C(5, 0) Triangle MNO: M(7,4)
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Answer:

y = 8

Step-by-step explanation:

Two triangles are said to be congruent if all the three sides and three angles of both triangles are equal.

The distance between two points on the coordinate plane is given as:

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\

In triangle ABC:

|AB|=\sqrt{(2-8)^2+(6-4^2)}=\sqrt{40} =2\sqrt{10}\\\\|AC|=\sqrt{(5-8)^2+(0-4)^2}=5\\\\|BC|=\sqrt{(5-2)^2+(0-6)^2    }=\sqrt{45}

In triangle MNO:

|MN|=\sqrt{(1-7)^2+(2-4^2)}=\sqrt{40} =2\sqrt{10}\\\\|MO|=\sqrt{(4-7)^2+(y-4)^2}\\\\|NO|=\sqrt{(4-1)^2+(y-2)^2    }

Since triangle ABC and triangle MNO are congruent, hence:

|AB| = |MN| = 2√10, |AC| = |MO| = 5, |BC| = |NO| = √45

|AC|=|MO|=5\\\\\sqrt{(4-7)^2+(y-4)^2}=5\\\\(4-7)^2+(y-4)^2=25\\\\9 +(y-4)^2=25\\\\(y-4)^2=16\\\\square\ root\ of\ both\ sides:\\\\y-4=4\\\\y=4+4\\\\y=8

Hence O = (4, 8)

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Step-by-step explanation:

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