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34kurt
3 years ago
6

Mark thinks the equation y=6x+4 will match the red solid graph. Mia thinks it will match the blue dotted graph. Who’s right? Exp

lain your answer.

Mathematics
1 answer:
Rudiy273 years ago
6 0

Answer:

Technically neither, but Mia is correct.

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Since our slope <em>m</em> is equal to 6, it is a positive number. That means that the slope/line will be positive, so the line should be going up, not down. That means the blue line would be correct. Therefore, Mia is correct.

Technicality:

Since the blue line is dotted, the equation should be a <em>inequality </em>and not a linear equation. No solutions on the line would technically work. If the equation was y < 6x + 4 or something with an inequality sign, then it would be correct.

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In the previous question you found 5% of £84 . Now use your answer to<br> increase £84 by 5%. *
Sergeu [11.5K]

Answer:

88.20

Step-by-step explanation:

100%-> 84

105%-> 88.20

6 0
2 years ago
When x=1, find the value of y<br><br> 1) -3<br> 2) -1<br> 3)1<br> 4)-4
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Answer:

y = -3

Step-by-step explanation:

The equation of the line is y = -x -2

We plug in the given x value into the equation to find y.

y = -(1) - 2

Simplify.

y = -3

3 0
2 years ago
Answer quickly please
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Answer:

linear I think so ................

3 0
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Three people pull simultaneously on a stubborn donkey. Jack pulls directly ahead of the donkey with a force of 90.5 N , Jill pul
Radda [10]

Answer:

Fn= 174.9 N : Magnitude of the net force the people exert on the donkey.

Step-by-step explanation:

We find the components of the forces in x-y-z

Force of  Jack in z   =F₁z=90.5 N in direction (+z)

Force of  Jill  in x     = F₂x= -82.3*cos45°= - 58.19 N (-x)

Force of  Jill  in y     =F₂y=-82.3*sin45°=   + 58.19 N (+y)

Force of  Jane  in x  =F₃x=125*cos45°=   + 88.4 N (+x)

Force of  Jane  in y   =F₃y=125*sin45°=   + 88.4  N (+y)

Calculating of the components of the net force the people exert on the donkey.

Fnx= F₂x+F₃x=( - 58.19+ 88.4 )N=30.2N (+x)

Fny= F₂y+F₃y=( 58.19+88.4 ) = 146.59 N (+y)

Fnz =F₁z=90.5 N  (+z)

Calculating of the magnitude of the net force the people exert on the donkey.

F_{n} =\sqrt{(F_{nx})^{2}+(F_{ny}) ^{2} +(F_{nz}) ^{2}   }

F_{n} =\sqrt{(30.2)^{2}+( 146.59) ^{2} +(90.5) ^{2}   }

F_{n} = 174.9 N

7 0
3 years ago
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