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Bad White [126]
3 years ago
5

Derrick grows vegetables on a circular patch of land. The radius of the patch is 16 meters. What is the approximate area of the

patch of land?
Mathematics
1 answer:
Bezzdna [24]3 years ago
6 0

Answer:

804m²

Step-by-step explanation:

Area = pi × r²

3.14 × 16²

803.84 m²

Approximately, 804m²

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The gym has a total of 25 treadmills and stationary bikes. there are seven more stationary bikes than treadmills.
Rudik [331]

The system of equations is t+b=25\\b=t+7

Step-by-step explanation:

We can answer this question as follows.

First of all, we call:

t = number of treadmills

b = number of stationary bikes

The two conditions that we have can be translated into equations as follows:

- The gym has a total of 25 treadmills and stationary bikes:

t+b=25

- There are seven more stationary bikes than treadmills:

b=t+7

So the system of equations to solve is

t+b=25\\b=t+7

We now solve it in the following way: first, we rewrite the second equation by bringing t on the left side,

t+b=25\\b-t=7

Now we add the 1st equation to the 2nd equation:

(t+b)+(b-t)=25+7\\t+b+b-t=32\\2b=32\\b=\frac{32}{2}=16

And therefore,

t+b=25\\t+16=25\\t=25-16=9

So, there are 16 stationary bikes and 9 treadmills.

Learn more about systems of equations:

brainly.com/question/13168205

brainly.com/question/3739260

#LearnwithBrainly

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3 years ago
John is a runner what is the speed if you Ran<br> hundred metter sprint in 10 seconds
Ahat [919]

Answer:

1000

Step-by-step explanation:

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3 years ago
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Answer:  see below

<u>Step-by-step explanation:</u>

17) 5n - 3 > -2n + 4     and    9 - 4n ≥ -2n + 1

   <u> +2n   </u>    <u> +2n      </u>              <u>    +2n </u>   <u>+2n      </u>

   7n - 3   >     4                    9 - 2n  ≥       1

        +3         +3                  -9                 -9

    7n       >      7                       -2n   ≥     -8

  <u> ÷7     </u>    <u>     ÷7  </u>                   <u> ÷ -2 </u>  ↓  <u> ÷ -2 </u>

          n  >     1         and            n   ≤   4                  

Graph:   o----------------- ·

              1                     4

18) 9k - 2 ≤ 9 + 10k < 9 - 4k

     9k - 2 ≤ 9 + 10k      and     9 + 10k < 9 - 4k

  <u> -10k     </u>    <u>     -10k </u>               <u>       +4k </u>   <u>    +4k  </u>

     -k - 2 ≤ 9                             9 + 14k < 9

   <u>      +2</u>   <u>+2         </u>                 <u> -9          </u>  <u>-9         </u>

     -k      ≤  11                                  14k  <  0

 <u> ÷ -1    </u>   ↓<u> ÷ -1  </u>                      <u>       ÷14 </u>    <u>÷14      </u>

          k  ≥ -11                and               k < 0

Graph:    · -----------------o

              -11                  0    

19) 4 - n ≤ 10 + 5n ≤ 6n + 1

     4 - n ≤ 10 + 5n       and     10 + 5n ≤  6n + 1

   <u>    -5n </u>   <u>      -5n  </u>                 <u>      -6n </u>   <u>-6n     </u>

   4 - 6n ≤ 10                           10  -  n  ≤       1    

  <u>-4        </u>  <u> -4            </u>              <u> -10        </u>    <u>  -10  </u>

        -6n ≤ 6                                    -n ≤   -9

   <u>  ÷ -6   </u>↓ <u>÷ -6     </u>                    <u>    ÷ -1 </u>↓<u> ÷ -1    </u>

           n ≥ -1              and                 n ≥ 9

Graph:    · -----------------→

              -9                  

20) 4p - 5 ≤ 2p + 9 ≤ 4p + 7

     4p - 5 ≤ 2p + 9     and     2p + 9 ≤ 4p + 7

  <u> -2p       </u>   <u>-2p    </u>                 <u> -4p    </u>   <u>-4p      </u>

    2p - 5 ≤         9                -2p + 9  ≤        7    

    <u>      +5   </u>  <u>    +5    </u>             <u>        -9  </u>    <u>     -9  </u>

       2p  ≤       14                   -2p       ≤      -2

   <u>  ÷ 2   </u>   <u>    ÷ 2     </u>               <u>÷ -2    </u> ↓<u>    ÷ -2    </u>

         p ≤       7          and         p    ≥      1

Graph:    · ----------------- ·

              1                    7

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