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Shtirlitz [24]
3 years ago
14

Use the figure to complete the proportion.

Mathematics
1 answer:
MAVERICK [17]3 years ago
6 0

Answer:

BE / AB = <u>HE</u> / AH

Step-by-step explanation:

AE is angle bisector

BE / HE = AB / AH

BE / AB = HE / AH

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Thepotemich [5.8K]

Answer:

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3 0
3 years ago
A circle has a diameter with endpoints at (6, 5) and (8, 5). Write the equation for the circle.
mario62 [17]

Answer:

(x-7)^2+(y-5)^2=1

Step-by-step explanation:

The two things that are required to formulate the equation of the circle is the center coordinate and the radius of the circle!

<u>Center of the circle:</u>

  • The center of the circle always lies at the midpoint of the endpoints of its diameter: Let's call the endpoints A(6,5) and B(8,5).

Using the midpoint formula we'll get:

(x_m, y_m) = \left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

(x_m, y_m) = \left(\dfrac{6+8}{2},\dfrac{5+5}{2}\right)

(x_m, y_m) = (7,5)

This is the center coordinate of our circle.

<u>Radius: </u>

The radius of the circle is the distance from the center of the circle to any of the endpoints of the diameter (A or B)

We can use the distance formula:

r = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

r = \sqrt{(x_1-x_m)^2+(y_1-y_m)^2}

r = \sqrt{(6-7)^2+(5-5)^2}

r = \sqrt{1^2}

r = 1

<u>Equation of the circle: </u>

The equation is written as:

(x-a)^2+(y-b)^2=r^2

here, (a,b) are the center points of the circle

in our case this is (a,b)=(x_m,y_m)=(7,5)

and r = 1

(x-7)^2+(y-5)^2=1^2

(x-7)^2+(y-5)^2=1

This is the equation of the circle!

3 0
3 years ago
Distance between (7,-1) and (),3)
Art [367]

Answer:

65

Step-by-step explanation:

3 0
3 years ago
*25 points!*
mariarad [96]
Pick 2 pairs of equations t<span>hen use addition and subtraction to eliminate </span>the same variable<span> from both pairs of equations then it is left with 2 variables 
</span>Pick two pairs
<span><span>4x - 3y + z = - 10</span><span>2x + y + 3z = 0
</span></span>eliminate the same variable from each system
<span><span>4x - 3y + z = - 10</span> 
<span>2x + y + 3z = 0</span> 

<span>4x - 3y + z = - 10</span> 
<span>-4x - 2y - 6z = 0</span> 

<span>-5y - 5z = - 10</span> 

<span>2x + y + 3z = 0</span> 
<span>- x + 2y - 5z = 17</span> 

<span>2x + y + 3z = 0</span> 
<span>-2x + 4y - 10z = 34</span> 

<span>5y - 7z = 34
</span></span>Solve the system of the two new equations:
<span><span>-5y - 5z = - 10</span> 
<span>5y - 7z = 34</span> 

<span>-12z = 24</span> 
which is , <span>z = - 2</span> 

<span>-5y - 5(- 2) = - 10</span> 
<span>-5y = - 20</span> 
wich is , <span>y = 4
</span></span>substitute into one of the original equations
<span>- x + 2y - 5z = 17</span> 
<span>- x + 2(4) - 5(- 2) = 17</span> 
<span>- x + 18 = 17</span> 
<span>- x = - 1</span> 
<span>x = 1</span> 
<span>which is , </span><span>(x, y, z) = (1, 4, - 2)</span><span> 
</span>Does 2(1) + 4 + 3(- 2) = 0<span> ? Yes</span><span>

</span>
7 0
3 years ago
Please help, it would really make my day! I’ll give branliest if it’s correct! :-)
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Answer:

28

Step-by-step explanation:

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3 years ago
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