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Aliun [14]
3 years ago
8

Pleawes helpppp what's the value of x ??

Mathematics
1 answer:
defon3 years ago
5 0

Answer:

J 28

Step-by-step explanation:

3x-10 = plug in x   for angle  C

84-10 = subtract   for angle  C

74 = C

3x/3 - B/2

For last Angle B always look for 180

74 + 50 = 124

180 - 124 = 56

(2x) = plug in x for angle B

56 = B

x = B/2

x = 3x/3 -B/2

x = 28

Hope this helps

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Answer:

It would be C.

Step-by-step explanation:

This is because they allow it to be 50 dollars and less, making it C.

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2 years ago
WCLN PCMath1l - Rev. Sept/2018
Verdich [7]

Answer:

\frac{p + 1}{p - 8}

Step-by-step explanation:

The  \: slope: \frac{2p + 1 - p}{p - 5 - 3}  =  \frac{p + 1}{p - 8}

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3 years ago
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Law Incorporation [45]

Answer:

(a) 900

(b) [567.35 , 1689.72]

(c) [23.82 , 41.11]

Step-by-step explanation:

We are given that a sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms i.e.;

Sample mean, xbar = 290      Sample standard deviation, s = 30  and  Sample size, n = 20

(a) Point estimate of the population variance is equal to sample variance, which is the square of Sample standard deviation ;

                         \sigma^{2}  =  s^{2} = 30^{2}

                          \sigma^{2}  = 900

(b) 90% confidence interval estimate of the population variance is given by the pivotal quantity of  \frac{(n-1)s^{2} }{\sigma^{2} } ~ \chi^{2} __n_-_1

P(10.12 < \chi^{2}__1_9 < 30.14) = 0.90 {At 10% significance level chi square has critical

                                           values of 10.12 and 30.14 at 19 degree of freedom}        

P(10.12 < \frac{(n-1)s^{2} }{\sigma^{2} } < 30.14) = 0.90

P(\frac{10.12}{(n-1)s^{2} } < \frac{1 }{\sigma^{2} } < \frac{30.14}{(n-1)s^{2} } ) = 0.90

P(\frac{(n-1)s^{2} }{30.14} < \sigma^{2} < \frac{(n-1)s^{2} }{10.12} ) = 0.90

90% confidence interval for \sigma^{2} = [\frac{19s^{2} }{30.14} , \frac{19s^{2} }{10.12}]

                                                   = [\frac{19*900 }{30.14} , \frac{19*900 }{10.12}]

                                                   = [567.35 , 1689.72]

Therefore, 90% confidence interval estimate of the population variance is [567.35 , 1689.72] .

(c) 90% confidence interval estimate of the population standard deviation is given by ;

       P(\sqrt{\frac{(n-1)s^{2} }{30.14}} < \sigma < \sqrt{\frac{(n-1)s^{2} }{10.12}} ) = 0.90

90% confidence interval for \sigma = [\sqrt{\frac{19s^{2} }{30.14}}   , \sqrt{\frac{19s^{2} }{10.12}}  ]

                                                 = [23.82 , 41.11]

Therefore, 90% confidence interval estimate of the population standard deviation is [23.82 , 41.11] .

7 0
3 years ago
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PtichkaEL [24]

Answer:

How much is 80 out of 100 written as a percentage? Convert fraction (ratio) 80 / 100 Answer: 80%

Step-by-step explanation:

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geniusboy [140]

Answer:

-1

Step-by-step explanation:

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3 years ago
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