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r-ruslan [8.4K]
2 years ago
11

Need help l don’t understand could someone help me?

Mathematics
2 answers:
alekssr [168]2 years ago
7 0

Answer:

first put the numbers and unknowns to different sides, as in 6x-3x= 14-5, now solve for x, 3x=9, divide each side by 3 to get the value of x, x=3

Step-by-step explanation:

nika2105 [10]2 years ago
3 0

I did it for you. (Step by step)

I hope this helps.

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Can someone smart please help me?
ollegr [7]
Hello! 

For a:

How I would do this, is I would first say if all 46 animals (heads) were chickens, how many legs would there be? Each chicken has 2 legs, so 46 * 2 = 92. The total amount of legs is 96 as stated in the question, so if all of the animals were chickens, the farmer would be 4 legs short.

Now to add rabbits into the equation. Rabbits have 4 legs, and chickens have 2. You want to find the difference between the two, because as you add rabbits to the animals the farmer has, then you have to take away chickens at the same time. 4-2 = 2, so for each rabbit you replace, you add 2 legs. 

Since the farmer is 4 legs short with all chickens, then you just divide that 4 by the 2 legs you add by replacing a chicken with a rabbit.

4 / 2 = 2 rabbits

So that means there are 2 rabbits. Since there are 46 heads in total, if 2 are rabbits, that means there are 44 chickens.

So there are 44 chickens and 2 rabbits.

b)

You can follow the same steps: I'm assuming all are child tickets for now:

3.05 * 100 = $305

And now you find how much money short you are.

498.6 - 305 = 193.6

Next, you find the difference in the ticket costs.

5.25 - 3.05 = 2.20

And you divide to find the number of adult tickets.

193.6 / 2.2 = 88

Since 100 tickets were sold, and 88 adult tickets were sold, that means 12 child tickets were sold.
7 0
3 years ago
CALCULUS: For the function whose values are given in the table below, the integral from 0 to 6 of f(x)dx is approximated by a Re
ladessa [460]

The table gives values of <em>f(x)</em> at various <em>x</em> in the interval [0, 6], and you have to use them to approximate the definite integral,

∫₀⁶ <em>f(x)</em> d<em>x</em>

with a left-endpoint sum using 3 intervals of width 2. This means you have to

• split up [0, 6] into 3 subintervals of equal length, namely [0, 2], [2, 4], and [4, 6]

• take the left endpoints of these intervals and the values of <em>f(x)</em> these endpoints, so <em>x</em> ∈ {0, 2, 4} and <em>f(x)</em> ∈ {0, 0.48, 0.84}

• approximate the area under <em>f(x)</em> on [0, 6] with the sum of the areas of rectangles with dimensions 2 × <em>f(x)</em> (that is, width = 2 and height = <em>f(x)</em> for each rectangle)

So the Riemann sum is

∫₀⁶ <em>f(x)</em> d<em>x </em>≈ 2 ∑ <em>f(x)</em>

for <em>x</em> ∈ {0, 2, 4}, which is about

∫₀⁶ <em>f(x)</em> d<em>x </em>≈ 2 (0 + 0.48 + 0.84) = 2.64

making the answer A.

7 0
2 years ago
A bucket is leaking. After 3 hours the bucket has leaked 3/4 of an ounce. How many ounces per hour is the bucket leaking?
Bogdan [553]
The bucket leaks 1/4 ounce per hour. Because the numerator is 3 and it took 3 hours, you can give 1/4 to every hour (3/4 divided by 3).
6 0
3 years ago
Solve please<br> A. 1/6m-3=-5<br> B. 2/3x-3=1/2x-7<br> C. x+x/2-4=x/4
AysviL [449]

Answer:

A m = 48

B x = -24

C x = 16

Step-by-step explanation:

A. 1/6m - 3 = 5

1/6m = 5+3

1/6m = 8

multiply both side by 6

m = 8×6

m = 48

B. 2/3x-3 = 1/2 x-7

2/3 x - 1/2 x = -7 +3

1/6 x = -4

multiply 6 to the both side

x = -4×6

x= -24

C.x+x/2-4= x/4

x+x/2 - x/4 = 4

x + l/2 x - 1/4 x = 4

1/4 x = 4

multiply both side by 4

x= 4×4

x = 16

4 0
2 years ago
9n - 2 - 6n - 3<br> I need help with question.
andrew11 [14]
9n - 2 - 6n - 3
(9n + -6n) + (-2+-3)
=3n -5
8 0
3 years ago
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