Answer:
5600N
Explanation:
Given parameters:
Mass of car = 700kg
Initial velocity = 10m/s
Final velocity = 30m/s
Displacement = 50m
Unknown:
Net force acting on the car = ?
Solution:
To find the force acting on a body, it is pertinent we know the mass and acceleration.
Force = mass x acceleration
Now;
Let us find the acceleration from the kinematics equations:
v² = u² + 2aS
v is the final velocity
u is the initial velocity
a is the acceleration
S is the distance
30² = 10² + (2 x a x 50)
900 = 100 + 100a
100a = 800
a = 8m/s²
Therefore;
Force = 700 x 8 = 5600N
Answer:
B). increasing
Explanation
its increasing but at a constant rate, its growing consistently
Answer:
so separation between slit is 0.12 mm
Explanation:
given data
slit wide = 0.020 mm
wavelength λ = 589.6 nm
fringe pattern n = 11
to find out
separation between the slits
solution
we know that for maxima we can say
d sinθ = m × λ .........1
and m is mth order maxima
and for central maxima
number of bright fringe is here
N = 2m -1
11 = 2m - 1
m = 6
so here number of maxima on either side of central maxima will be m-1
that is = 5
because we know 6th maxima will be minimized by minima
so
condition for minima is
a sin(θ) = n × λ
now for 1st minima
a sin(θ) = λ
and
= m
d = ma
d = 6 × 0.02
d = 0.12 mm
so separation between slit is 0.12 mm
Given that the space station is free of gravitational force, it is required that it spins an certain speed to acquire centripetal acceleration.
In this case, you want that the centripetal acceleration, Ac, equals g (gravitational acceleration on the earth), becasue this will cause a centripetal force equal to the weight on earth.
The formula for centripetal acceleration is Ac = [angular velocity]^2*R
where R = [1/2]50.0m = 25.0 m
Ac = 9.81 m/s^2
=> [angular velocity]^2 = Ac/R = 9.81m/s^2v/ 25.0m = 0.3924 (rad/s)^2
[angular velocity] = √(0.3924) rad/s = 0.63 rad/s
Answer: 0.63 rad/s
Answer:
The rate of change of the shadow length of a person is 2.692 ft/s
Solution:
As per the question:
Height of a person, H = 20 ft
Height of a person, h = 7 ft
Rate = 5 ft/s
Now,
From Fig.1:
b = person's distance from the lamp post
a = shadow length
Also, from the similarity of the triangles, we can write:
Differentiating the above eqn w.r.t t:
Now, we know that:
Rate =
Thus