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3 years ago

Why did thomson’s results from experimenting with cathode rays cause a big change in scientific thought about atoms?

Physics

1 answer:

natima [27]3 years ago

3 0

Answer:

Explanation:

Before Thomson's discovery, atoms were believed according to the "Dalton's atomic theory" to be the smallest indivisible particle of any matter. This makes atoms the smallest unit of a matter.

Thomson in 1897, used the discharge tube to discover cathode rays which are today called electrons.

The discovery of electrons provided more light into the structure and nature of atoms. Atoms were now being seen in a different light as particles that are made up of other smaller sized particles.

Thomson through his experiment was able determine perfectly well the nature of the rays he saw emanating from the cathode. One of his findings shows that the rays are negatively charged and are repelled by negative charges.

The discovery of electrons further led to more works on the atom and other particles were discovered. Atoms were no longer seen as indivisible or the smallest particles of matter.

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An alternating source drives a series RLC circuit with an emf amplitude of 6.34 V, at a phase angle of +33.3°. When the potentia

Katena32 [7]

Answer:

V $_{L}$ =- 8.78v

Explanation:

$E^{2} _{m}$ = $V^{2} _{R}$ + $(V_{L} -V _{C} )^{2}$

OR V $_{L}$ = V $_{c}$ + $\sqrt{E^{2}{m} - V^{2} {R} }$

where VR = E ${m}$ cosФ

V $_{L}$ = V $_{c}$ + $\sqrt{E^{2}_{m} - E^{2}_{m} cos^{2} }$ Ф

V $_{L}$ = V $_{c}$ + ${E_{m} \sqrt{1 - cos^{2} } }$ Ф

V $_{L}$ = V $_{c}$ + E $_{m}$ sinФ

substituting the given values

V $_{L}$ = 5.33 + 6.34 x sin33°

V $_{L}$ = -8.78v

8 0

3 years ago

Read 2 more answers

How many x-ray photons per second are created by an x-ray tube that produces a flux of x rays having a power of 1.00 W

ArbitrLikvidat [17]

Complete question:

How many x-ray photons per second are created by an x-ray tube that produces a flux of x rays having a power of 1.00 W. Assume the average energy per photon in 78.0 keV.

Answer:

The number of x-ray photons per second created by the x-ray tube is 8.01 x 10¹³ photons/sec

Explanation:

Given;

power of the flux produced, P = 1 W = 1 J/s

energy per photon, E = 78 keV

Convert the energy per photon to J

E = 78 x 10³ x 1.6 x 10⁻¹⁹ = 1.248 x 10⁻¹⁴ J / photon

let the number of photons = n

n(1.248 x 10⁻¹⁴ J / photon) = 1 J/s

$n = \frac{1 \ J/s}{1.248 \times 10^{-14}\ J/photon } = 8.01 \times 10^{13} \ photons/s$

Therefore, the number of x-ray photons per second created by the x-ray tube is 8.01 x 10¹³ photons/sec

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2 years ago

The box in the above picture is falling from the top of a building to the ground. Two major forces are acting on the box as it f

Darya [45]

I need to see the picture. It is either gravity or air resistance (friction)

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3 years ago

The form of energy in fossil fuels is what kind of energy?

Nonamiya [84]

Solar energy or sunlight...

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2 years ago

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A machinist with normal vision has a near point at 25 cm. The machinist wears eyeglasses in order to do close work. The power of

Alik [6]

Answer:

17.4 cm

Explanation:

Power of lens = +1.75 diopters

Focal length of lens

$f=\frac{100}{1.75}=\frac{400}{7}$

This is a convex lens as focal the diopter given is positive which makes the focal length positive. Image distance will be negative.

v = -25

$\frac{1}{v}-\frac{1}{u}=\frac{1}{f}\\\Rightarrow \frac{1}{-25}-\frac{1}{u}=\frac{1}{\frac{400}{7}}\\\Rightarrow -\frac{1}{u}=\frac{7}{400}+\frac{1}{25}\\\Rightarrow \frac{1}{u}=-\frac{7}{400}-\frac{1}{25}\\\Rightarrow \frac{1}{u}=-0.0575\\\Rightarrow u=-17.4\ cm$

∴ The new near point is 17.4 cm

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3 years ago