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3 years ago

A projectile is launched with an initial velocity of (40 m/s), at an angle of (30°) above

Physics

1 answer:

zlopas [31]3 years ago

8 0

Answer:

330.5 m

Explanation:

In this case, the object is launched horizontally at 30° with an initial velocity of 40 m/s .

The maximum height will be calculated as;

$h=\frac{v^2_isin^2\alpha }{2g}$

where ∝ is the angle of launch = 30°

vi= initial launch velocity = 40 m/s

g= 10 m/s²

h= 40²*sin²40° / 2*10

h={1600*0.4132 }/ 20

h= 661.1/2 = 330.5 m

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Dr. Smith is conducting an experiment to determine if paintings of landscapes produce more peaceful feelings than abstract paint

skad [1K]

The option that could be the hypothesis for this experiment is that D. Abstract paintings may elicit feelings of stress as students try to determine the meanings of the paintings; therefore, abstract paintings may cause college students to report lower feelings of peace.

<h3>What is a hypothesis?</h3>

It should be noted that a hypothesis simply means the proposed explanation made on the basis of limited evidence.

From the information, Smith is conducting an experiment to determine if paintings of landscapes produce more peaceful feelings than abstract paintings.

Therefore, the option that could be the hypothesis for this experiment is that abstract paintings may elicit feelings of stress as students try to determine the meanings of the paintings; therefore, abstract paintings may cause college students to report lower feelings of peace.

Learn more about hypothesis on:

brainly.com/question/11555274

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3 0

2 years ago

When the starter motor on a car is engaged, there is a 310 A current in the wires between the battery and the motor. Suppose the

Blababa [14]

Answer:

Diameter will be 351.42 mm

Explanation:

We have given current flowing in the copper wire i = 310 A

Voltage drop across the wire V = 0.55 volt

We know that resistance is given by $R=\frac{V}{i}=\frac{0.55}{310}=0.00177\Omega$

Length of the copper wire l = 1 m

Resisitivity of the copper wire $\rho =1.72\times 10^{-8}\Omega m$

We know that resistance $R=\frac{\rho l}{A}$

$0.00177=\frac{1.72\times 10^{-8}\times 1}{A}$

$A=969.4545\times 10^{-8}m^2$

As area $A=\pi r^2$

$3.14\times r^2=969.4545\times 10^{-8}$

$r=17.57\times 10^{-4}m$

So diameter $d=17.57\times 10^{-4}\times 2=35.142\times \times 10^{-4}m$ = 351.42 mm

3 0

4 years ago

Is salt an element or a compound

LiRa [457]

Hello!

To answer your question, salt is a compound!

It is the product of the chemical bond between Na (Sodium) and Cl (Chloride),

Hopes this help you with your question.

5 0

4 years ago

Radar is used to determine distances to various objects by measuring the round-trip time for an echo from the object. (a) How fa

BartSMP [9]

Answer

given,

Echo time = t = 1000 s

speed = ?

$v = \dfrac{d}{t}$

a) speed of electromagnetic wave

$c = \dfrac{d}{t}$

wave travels Venus two time

$c = \dfrac{2d}{t}$

$d = \dfrac{ct}{2}$

$d = \dfrac{3 \times 10^8\times 1000}{2}$

d = 1.5 x 10¹¹ m

b) now, echo time

$c = \dfrac{2d}{t}$

$t = \dfrac{2d}{c}$

$t = \dfrac{2\times 75}{3 \times 10^8}$

t = 5 x 10⁻⁷ s

8 0

3 years ago

a current of 5 ampere is passed for 2 hours in an electric iron having a resistance of 100 ohms calculate the heat produced

Alina [70]

Answer:

$\boxed{\sf Heat \ produced \ (H) = 5 \ kWh}$

Given:

Resistance (R) = 100 Ω

Current (I) = 5 A

Time (t) = 2 hours

To Find:

Heat developed (H) in the electric iron

Explanation:

Formula:

$\boxed{ \bold{ \sf H = I^2Rt}}$

Substituting values of I, R & t in the equation:

$\sf \implies H = {5}^{2} \times 100 \times 2 \\ \\ \sf \implies H = 25 \times 100 \times 2 \\ \\ \sf \implies H = 5000 \\ \\ \sf \implies H = 5 \: kWh$

$\therefore$

Heat developed (H) in the electric iron = 15 kWh

3 0

3 years ago