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3 years ago

Can someone give me 5 differences for each velocity and speed. FOR EACH...

Physics

2 answers:

VARVARA [1.3K]3 years ago

5 0

Answer:

132-123+ere

Explanation:

sdsdsd

QveST [7]3 years ago

5 0

Sorry wish I could help try looking it up on google!

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a large heavy truck and a baby carriage roll down a hill. Neglecting friction, at the bottom of the hill, the baby carriage will

sveticcg [70]

Answer:

please give me brainlist and follow

Explanation:

At the bottom of the hill, the baby carriage will likely have less momentum Therefore, option D is correct. Solution: ... Therefore, at the bottom of the hill, the heavy truck will have more momentum and baby carriage will have less momentum.

8 0

3 years ago

How long would a circuit be connected to produce a current of 0.65 A with a charge of 380 C?

drek231 [11]

Answer:

what grade are you dude

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3 years ago

Will the body be travelling with a constant speed or a constant acceleration if the distance travelled by the body is directly p

Anna35 [415]

Distance ( say d ) is directly proportional to time ( say t ) .
mathematically ,
d = kt
where k is constant if proportionality .
Now differentiating the above equation with respect to time ,
we get ;
v = k
=> velocity is constant .
=> No acceleration .

6 0

3 years ago

Anuja is holding a stuffed dog, with a mass of 0.30 kg, when Derek decides that he wants it and tries to pull it away from Abuja

igor_vitrenko [27]

Answer:

a = 3.33 m/s²

Explanation:

The horizontal acceleration of the dog can be found by using Newton's Second Law of Motion as follows:

F = ma

where,

F = Unbalanced force applied on the dog = 11 N - 10 N = 1 N

m = mass of the dog = 0.3 kg

a = horizontal acceleration of dog = ?

Therefore,

1 N = 0.3 kg(a)

a = 1 N/0.3 kg

8 0

3 years ago

At a particular instant the magnitude of the gravitational force exerted by a planet on one of its moons is 7 × 1021 N. Collapse

9966 [12]

Answer:

Fg = 4.2*10²² N

Explanation:

The gravitational force between any two masses, provided that can be approximated by point masses (comparing their diameters with the distance between them), obeys the Newton's Universal Law of Gravitation, which states that the force (always attractive) is proportional to the product of the masses and inversely proportional to the square of the distance between them (this as a consequence of our Universe being three-dimensional), as follows:

$Fg =\frac{G*m1*m2}{r^{2}}$

So, if one of the masses increases 6 times, the force between them will be directly 6 times larger, so the new magnitude of the force will be as follows:

Fg₂ = Fg₁*6 = 7*10²¹ N* 6 = 4.2*10²² N

7 0

3 years ago