Answer:D
Explanation: acorrding to my calculation of my 8th grade education with the proxsimity of the y=mx+b you will get -397758.4837y483 now you multiply that times pi which is 3.145926535 8979323846 2643383279 5028841971 6939937510 5820974944 5923078164 0628620899 8628034825 3421170679 and you get 42066669 divide that by 3 and you get D
Answer:
Efficiency
Explanation:
- The amount of mechanical work an engine can do per unit of heat energy it uses is called its efficiency.
- It is also defined as the output divided by the total electrical power consumed.
- In terms of heat, efficiency of engine is given by :
are output heat and input heat respectively.
Hence, the correct option is (d) "efficiency"
Answer:
c)wind
Explanation:
Wind from the given choices will have the greatest amount of kinetic energy.
Kinetic energy is the energy due to motion of a body. It is different from the energy at rest in a body.
- Wind is air in motion.
- Wind energy is a form of kinetic energy in motion.
A book on a table, a slice of pizza and a person at the top of the stairs are all at rest and will possess potential energy.
Answer:
vf = 14.2176 m/s
Explanation:
Given
m = 4 Kg
viy = 7.00 ĵ m/s
Fx = 11.0 î N
t = 4.5 s
vf = ?
Using the Impulse - Momentum Theorem, we have
F*Δt = m*Δv ⇒ F*Δt = m*(vf - vi)
⇒ vf = (F*Δt + m*vi) / m
⇒ vf = (F*Δt + m*vi) / m
For <em>x-component</em>
⇒ vfx = (Fx*Δt + m*vix) / m = (11 N*4.5 s + 4 Kg*0 m/s) / (4 Kg)
⇒ vfx = 12.375 î m/s
For <em>y-component</em>
⇒ vfy = (Fy*Δt + m*viy) / m = (0 N*4.5 s + 4 Kg*7 m/s) / (4 Kg)
⇒ vfy = 7 ĵ m/s
Finally:
vf = √(vfx² + vfy²)
⇒ vf = √((12.375 m/s)² + (7 m/s)²)
⇒ vf = 14.2176 m/s
Answer:
0.99 seconds
Explanation:
The problem depicts a simple harmonic motion.
Now, from Hooke's law,
The spring constant is given as;
k =F/x
where:
x is the displacement of the spring's end from its equilibrium position
F is the restoring force exerted by the spring on that end
From the question, F = 20N while x = 10cm = 0.1m. Thus,
K = 20/0.1 = 200 N/m
Now, time to take for the mass to return to its starting point is a period
The period oscillation of the mass is given as;
T = 2π√m/k
Where m = mass = 5kg
T = 2π√(5/200)
T = 0.99 s
