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jeka94
4 years ago
13

If two point sources that create circular waves are moved closer together, what happens to the spacing between the nodal and ant

i-nodal lines? a. The spacing increases. c. The spacing stays the same. b. The spacing decreases. d. None of the above.
Physics
1 answer:
Dennis_Churaev [7]4 years ago
8 0

<span>The distance between the sources of a two point surface interference determines the number of lines that can be created for the nodal and anti-nodal lines. When the sources are moved closer together, the number of lines becomes minimal. Thus, the spaces between the lines become bigger. The answer to this item is letter A. The spacing increases. </span>

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The voltage applied across a given parallel-plate capacitor is doubled. How is the energy stored in the capacitor affected?
ikadub [295]

Answer:

The energy stored in the capacitor quadruples its original value.

Explanation:

The energy stored in a capacitor is given by the equation

U=\frac{1}{2}CV^2

where

C is the capacitance

V is the voltage across the plates

The capacitance, C, depends only on the properties of the capacitor, so it does not change when the voltage applied is changed.

Instead, in this problem the voltage applied is doubled:

V' = 2V

So the new energy stored is

U'=\frac{1}{2}C(2V)^2=4(\frac{1}{2}CV^2)=4U

so, the energy stored has quadrupled.

8 0
3 years ago
Which is NOT considered as a property of electromagnetic waves: 5
OlgaM077 [116]

Answer:

require a medium to propagate

Explanation:

this is because electromagnetic waves can travel through vacuum at the speed of 3.0 x 10^8 m/s

because they don't need particles to transfer energy

hope this helps

4 0
3 years ago
HELP ME 100 POINTS PLEASE BRAINIEST IF CORRECT!!!!!!!
WITCHER [35]

Answer:

a

Explanation:

the color reflected is the color you see

7 0
3 years ago
Read 2 more answers
I would appreciate some help.
motikmotik
You oughtta be able to do this one.

The "efficiency" is just the portion of the input work that
comes out in a useful form.

If the efficiency is 70%, that tells you that however much work
you put INto the machine, the machine will do 70% of that much
work for you at the output side.

Put 20,000 J in ... out comes (0.70) x (20,000 J)  =  14,000 J .

What happens to the other 30% of the work you put into it ?
It turns into HEAT.  That's why machines always have to be
cooled somehow while they're running.  
 
4 0
3 years ago
Two hundred turns of (insulated) copper wire are wrapped around a wooden cylindrical core of cross-sectional area 1.20 × 10−3 m2
Novosadov [1.4K]

Answer:

The charge flows through a point in the circuit during the change is 0.044 C.

Explanation:

Given that,

Number of turns in the copper wire, N = 200

Area of cross section, A=1.2\times 10^{-3}\ m^2

Resistance of the circuit, R = 118 ohms

If an externally applied uniform longitudinal magnetic filed in the core changes from 1.65 T in one direction to 1.65 T in the opposite direction.

We need to find the charge flows through a point in the circuit during the change. Due to change in magnetic field an emf is induced in it. It is given by :

\epsilon=\dfrac{d\phi}{dt}

Using Ohm's law :

\epsilon=IR

IR=-\dfrac{d\phi}{dt}\\\\I=-\dfrac{1}{R}\dfrac{d\phi}{dt}

Electric current is equal to the rate of change of electric charge. So,

dq=\dfrac{NA(B(0)-B(t))}{R}\\\\dq=\dfrac{200\times 1.2\times 10^{-3}(1.65+1.65)}{18}\\\\dq=0.044\ C

So, the charge flows through a point in the circuit during the change is 0.044 C.

4 0
3 years ago
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