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RUDIKE [14]
3 years ago
6

I WILL GIVE BRAINLIEST FOR FULL PROOF! no trolls!!!

Mathematics
2 answers:
Alex Ar [27]3 years ago
5 0

Answer:

AE = CF .

Why?

BD acts as a shape bisector because it cuts the entire rectangle in half from points B and D.

Given that <u>AE is perpendicular to BD</u>, and <u>CF is perpendicular to BD</u> (which we know BD is a bisector), that means that both AE and CF are of equal length inside the rectangle.

Another way to look at it is:

AE = CF because they are technically just vertical angles, shifted and displaced in a weird way; it is a different representation of vertical angles, only distorted. <em>(Don't use this as your answer though, it needs more context. I just want to make it look easier to comprehend.)</em>

lana [24]3 years ago
4 0

Answer:

i aggre with notjadereyes

Step-by-step explanation:

(pls nu report) i'm saying she's right all the way

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A certain kite has exactly one acute angle, and it measures 16 degrees. What is the maximum whole-number measure of the angle op
kvv77 [185]

Answer:

In order to do so, we need to use basic algebra. The angles in a kite add up to 360 degrees. so we form the following equation.

x + y + y + 16 = 360

x + y + y = 344 <----(360 -16)

Each letter or variable represents an angle measure. the measures of the three angles left. The 16 degrees is on the bottom of the kite and the angle opposite is the top angle. the two side angles will be the same measure that's why they are both y.

x + 2y = 344

The two side angles will be 90 or greater because there is only 1 acute angle. 90 is the smallest number that can be chosen. so we do the following.

Step-by-step explanation:

x + 2(90) = 344

x + 180 = 344

x = 344-180

x = 164

THE MAXIMUM WHOLE NUMBER MEASURE OF THE ANGLE OPPOSITE OF THE 16 DEGREE ACUTE ANGLE IS 164 DEGREES*

4 0
3 years ago
Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 b
jeka94

Answer:

Step-by-step explanation:

From the given information; Let's assume that  R should represent the set of all possible outcomes generated from  a bit string of length 10 .

So; as each place is fitted with either 0 or 1

\mathbf{|R|= 2^{10}}

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0

Now;

if  a 0 bit and a 1 bit are equally likely

The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

\mathbf{P(E) = \dfrac{|E|}{|R|}}

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:

\mathbf{{|E|}=1 }   ; \mathbf{|R|= 2^{10}}

\mathbf{P(E) = \dfrac{1}{2^{10}}}

4 0
3 years ago
A company invests $32000. after 4 years of growth at the same rate each year, the investment is worth $42692. find the annual gr
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Answer:

R = 33.35%

Step-by-step explanation:

that is the solution above

6 0
2 years ago
A train travels 80 miles per hour. If its speed remains the same, how far will the train have gone in 90 minutes?
Nataly_w [17]
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