Answer:
1GHU,TTTTTTTTTTTTTTTTTTTTTTTTTTTTTT
Explanation:
Answer:
<h2>
Histone acetylation increase transcription.
</h2><h2>
Whereas DNA methylation decrease transcription
</h2>
Explanation:
Histone acetylation is a transcription-activating modification which occurs by the addition of acetyl group from acetyl coenzyme A, to one or more lysine residues at the ε-amino group by the enzyme histone acetyltransferases. Histone acetylation increase transcription.
DNA methylation is one of the mechanisms that cells use to control gene expression and DNA become unavailable for transcription . In DNA methylation, DNA become inactive( unavailable for transcription) so that transcription wouldn't occur.
* More than 40 proteins and glycoproteins involved in the complement system are synthesized by the liver, macrophages, epithelial cells, they are present in the blood in plasmatic form, membrane, some have an enzymatic activity, regulator or membrane receptorThese are elements of the humoral innate immune response, they fight infections, purify immune complexes and apoptotic bodies.
<span>There are indeed three ways to activate the complement:</span>
Classical pathway: Activated by Immunoglobulins in immune complexes, aggregated Immunoglobulins, DNA, CRP, apoptotic bodies .......it involves nine fractions, starting with C1, then C4, C2, C3, to form a classical C5 convertase, then, activation of C5, C6, C7, C8, C9.
Alternative pathway: activated by polysaccharides (bacterial endotoxin), vascular wall poor in sialic acid, aggregated IgE ...C3b like is the first component in the alternate channel cascade, it will create an amplification loop, and form an alternative C5 convertase.
Lecithin pathway: Activated by mannose, fucose (carbohydrate of microorganisms)The first component is the complex MBL / MASP1 / MASP2: "mannose-binding protein": works according to the same principle as the complex C1 of the classical way (MASP2 cleaves the C4 and the rest of the cascade is equivalent to that of the classical way).
the three ways have the same outcome: A C5 convertase (formed by one of the pathways) cleaves C5 into C5a and C5b: C5b is deposited far from other fractions on the antigenic surface. The fixation of C5b in the cell is followed by that of C6, C7, C8, and C9 (9 molecules of C9): formation of the membrane attack complex (MAC) ==> Death of the cell by osmotic shock
Answer:
Both processes release energy for cell use. The products of one process are used as reactants by the other process. The reactants of one process are also the reactants of the other process.
Explanation:
