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polet [3.4K]
3 years ago
6

What are the solutions to the equation 3(x-4)(x+5)=0

Mathematics
1 answer:
VMariaS [17]3 years ago
6 0

Answer:

the solutions are 4 and -5

Step-by-step explanation:

3(x-4)(x+5)=0\\\\(x-4)(x+5)=0\\\\x-4=0\\\\x=4\\\\x+5=0\\\\x=-5

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Help me please i don't know what to do
astra-53 [7]

Answer:

a. a = 1, b = -5, c = -14

b. a = 1, b = -6, c = 9

c. a = -1, b = -1, c = -3

d. a = 1, b = 0, c = -1

e. a = 1, b = 0, c = -3

Step-by-step explanation:

a. x-ints at 7 and -2

this means that our quadratic equation must factor to:

(x-7)(x+2) = 0

FOIL:

x^2 + 2x - 7x - 14 = 0

Simplify:

x^2 - 5x - 14 = 0

a = 1, b = -5, c = -14

b. one x-int at 3

this means that the equation will factor to:

(x-3)^2=0

FOIL:

x^2 - 3x - 3x +9 = 0

Simplify:

x^2 - 6x + 9 = 0

a = 1, b = -6, c = 9

c. no x-int and negative y must be less than 0

This means that our vertex must be below the x-axis and our parabola must point down

There are many equations for this, but one could be:

-x^2-x-3=0

a = -1, b = -1, c = -3

d. one positive x-int, one negative x-int

We can use any x-intercepts, so let's just use -1 and 1

The equation will factor to:

(x+1)(x-1)=0

This is a perfect square

FOIL:

x^2-1=0

a = 1, b = 0, c = -1

e. x-int at \sqrt{3} , -\sqrt{3}

our equation will factor to:

(x+\sqrt{3} )(x-\sqrt{3)} =0

This is also a perfect square

FOIL and you will get:

x^2 - 3 = 0

a = 1, b = 0, c = -3

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1 year ago
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Jason wanted to buy postcards for his cousin. The price was 2 cards for $1. He had some change in his pocket. What combination o
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Answer:

2 dimes, 1 nickel and 3 quarters.

Step-by-step explanation:

The price of 2 postcards is $1. Any combination of coins that adds to $1 will work here. Remember, a penny is worth 0.01, a nickel is worth 0.05, a dime is worth 0.10, and a quarter is worth 0.25.

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