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Korolek [52]
3 years ago
15

Can someone help me solve this math equation? The answer is suppose to be 1 because that's what it says on my book but I got -1

as an answer?
|-24| ÷ [4(9-15)]
Mathematics
2 answers:
svetoff [14.1K]3 years ago
5 0

Answer:

it is 1

Step-by-step explanation:

EleoNora [17]3 years ago
5 0

Answer:

The answer is -1

Step-by-step explanation:

You find the absolute value of -24 which is 24

Then you multiply 4x(-6) to get -24

24 ÷ -24 = -1

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What is the value of the 7 in the number 53.75?<br> Give your answer as a fraction
Romashka [77]

Answer:

i think its 3/4

Step-by-step explanation:

hope that helps

8 0
3 years ago
The sum of two consecutive even integers is 86. find the two integers <br>​
lakkis [162]

Answer:

42 and 44

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
1.) Use the Pythagorean Theorem to determine if a triangle with side lengths 28ft., 45ft., 53ft. is a right triangle.
Alenkasestr [34]

Answer:

1. Right Triangle

2. Not Right Triangle

3. Not Right Triangle

Step-by-step explanation:

1. 28² + 45² = 2809 --> 53² = 2809

2. 6² + 6² = 72 --> 8² = 64

3. 4² + 10² = 116 --> 12² = 144

8 0
4 years ago
Pls help me with this question!!!
ankoles [38]

Answer: $2/child and $4/adult

Step-by-step explanation:

The total fare is $14 for 2 adults and 3 children

x is the child's fare

y is the adults fare

We can say:

1)  3x + 2y = $14

2)  We are told that x = (1/2)y  [each child's fare is 1/2 each adult's fare]

3) use (2) in (1)

  3x + 2y = $14

  3(1/2)y + 2y = $14

 (3/2)y + 2y = $14

  (7/2)y = $14

  y = ($14)*(2/7)

  y = $4/adult

   x = (1/2)y; x = (1/2)(4)

   x = $2/child

Check:  Does 3x + 2y = $14 when x = $2/child and y = $4/adult?

    3x + 2y = $14

    3($2/child) + 2($4/adult) = $14

      $6   +   $8 = $14   YES

6 0
3 years ago
Let the vector \mathbf{v}v have an initial point at (1, -2)(1,−2) and a terminal point at (0, 0)(0,0). Plot the vector \mathbf{v
ASHA 777 [7]

Given that the initial point of the vector is (1,-2) and the termination point of the vector is (0,0).

So, the tail of the vector is at point (1,-2) and the head of the vector is at (0,0). The vector, \vec{v}, has been shown in the figure.

The magnitude of the vector:

|\vec{v}|=\sqrt{(1-0)^2+(-2-0)^2}=\sqrt{1+4}=\sqrt{5}

The direction of a vector is the angle made by a vector with the positive direction of the x-axis.

From the figure, \theta = 180 \degree\tan ^{-1} \left|\frac {0-(-2)}{0-1}\right|

\theta = 180 ^{\circ} - \tan^{-1}(2) = 180 ^{\circ} - 63.43^{\circ}

\theta =116.57 ^{\circ}

Hence, the required vector having a magnitude \sqrt {5} and direction 116.57 ^{\circ} has been shown in the figure.

4 0
4 years ago
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