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vlabodo [156]
3 years ago
6

The width of a rectangle field is 3h yards and its length is 3 yards longer than the width. The field has a fence around its per

imeter with a gate 4 yards wide as shown below. Right in expression for the perimeter of the rectangular fields in terms of h excluding the width of the gate

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
8 0

Answer:

Part a) P=(12h+2)\ yd

Part b) The expression that represent the cost of fencing the field is (336h+56)

Part c) \$1,736

Step-by-step explanation:

<u>The complete question in the attached figure</u>

Part a) we know that

The perimeter of the rectangular field (excluding the width of the gate) is equal to

P=2(L+W)-4

we have

L=(3h+3)\ yd\\W=3h\ yd

substitute the given values

P=2(3h+3+3h)-4

P=2(6h+3)-4\\P=12h+6-4\\P=(12h+2)\ yd

Part b) we know that

To find out the cost of fencing the field (excluding the gate) , multiply the perimeter by the cost of $28 per yard

so

28(12h+2)=336h+56

Part c) we have

h=5

substitute the value of h in the expression of the cost

336(5)+56=\$1,736

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Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

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The parameters are:

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In this problem:

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The third defective bulb is the fifth bulb if:

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Hence:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

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More can be learned about the hypergeometric distribution at brainly.com/question/24826394

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