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vlabodo [156]
4 years ago
6

The width of a rectangle field is 3h yards and its length is 3 yards longer than the width. The field has a fence around its per

imeter with a gate 4 yards wide as shown below. Right in expression for the perimeter of the rectangular fields in terms of h excluding the width of the gate

Mathematics
1 answer:
d1i1m1o1n [39]4 years ago
8 0

Answer:

Part a) P=(12h+2)\ yd

Part b) The expression that represent the cost of fencing the field is (336h+56)

Part c) \$1,736

Step-by-step explanation:

<u>The complete question in the attached figure</u>

Part a) we know that

The perimeter of the rectangular field (excluding the width of the gate) is equal to

P=2(L+W)-4

we have

L=(3h+3)\ yd\\W=3h\ yd

substitute the given values

P=2(3h+3+3h)-4

P=2(6h+3)-4\\P=12h+6-4\\P=(12h+2)\ yd

Part b) we know that

To find out the cost of fencing the field (excluding the gate) , multiply the perimeter by the cost of $28 per yard

so

28(12h+2)=336h+56

Part c) we have

h=5

substitute the value of h in the expression of the cost

336(5)+56=\$1,736

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If we measured the heights of different plants and got 50”, 55”, 48”, 50” and 52”. What
mr Goodwill [35]

Answer:

B

Step-by-step explanation:

50+55+48+50+52=255

255/5=51

Anwser 51

5 0
3 years ago
What will be angle COD If: angle COD minus angle KOD equals 61degrees and angle COD minus angle KOC equals 53degrees?
kenny6666 [7]

Use algebra for such problems
let, Angle COD = x
Angle KOD = y
Angle KPC = z
Given ,. x - y = 61° ( Equation 1 )
x - z = 53° ( Equation 2 )
Subtract 1st equation from 2nd and you'll get :

z - y = 8° ( Equation 3 )
Now since , x + y + z = 180° ( Equation 4 )
Add Equation 3 to Equation 4 and you'll get
x + 2z = 188° ( Equation 5)
From Equation 2 we know that , x -z = 53°
or, x = 53° + z ( Equation 6 )
Put this value of 'x' in Equation 5 and solve for z. you'll get :
(53° + z) + 2z = 188°
or
3z = 188 - 53 = 135°
solving for z we get
z = 45°
put this value of z in Equation 5
x + ( 2 x 45° ) = 188°
or
x = 188° - 90° = 98°
hence , Angle COD = 98°














5 0
3 years ago
HElp me find the IQR please
patriot [66]
The interquartile range is 4
8 0
2 years ago
Bilal's fishing line was on a spool with a radius of 4cm. Suddenly, a fish pulled on the line, and the spool spun 16 times befor
Aleks [24]

First, I'd like to say that this question is flawed because the diameter of the spool changes as you pull the line out. Some would argue it's negligible I suppose.

At any rate, assuming there's a magic spool where the diameter doesn't change, let's find the cicumference so we can find the length of one wrap around the spool.

circumference = 2*pi*r = 2 * pi * 4cm = about 25.133 cm

Now if it turns 16 times we'll have 16 times the circumference.

16 * (25.133 cm)

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8 0
3 years ago
Read 2 more answers
The figure shows the front side of a purse in the shape of a trapezoid.
attashe74 [19]
For this case, what you must do is take out the area of two triangles and add it to the area of a rectangle to find the total area.
 We have then:
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 Total area:
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8 0
3 years ago
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