We have the slope m = (6-3)/(4-1) = 3/3 = 1;
Then, y - 3 = 1·( x - 1);
finally, y = x + 2.
Answer:
1/2 -2/1
Step-by-step explanation:
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Answer:

Step-by-step explanation:
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<u>Distance formula</u>

Let P(x, y) = any point on the locus
Let A = (0, 2)
Let B = (-2, 3)
If a point moves such that its distance from (0, 2) is one third distance from (-2, 3):

Therefore, using the distance formula:

Square both sides:
![\implies x^2+(y-2)^2=\dfrac{1}{9}[(x+2)^2+(y-3)^2]](https://tex.z-dn.net/?f=%5Cimplies%20x%5E2%2B%28y-2%29%5E2%3D%5Cdfrac%7B1%7D%7B9%7D%5B%28x%2B2%29%5E2%2B%28y-3%29%5E2%5D)

Multiply both sides by 9:



Did it step by step , hope it helps !