5/5 will be a whole, when it comes to 5ths, since she spent 2/5 of her money, 5/5 - 2/5, she has left 3/5 of the whole then.

then she spent 4/9 of her 3/5 leftover, how much is 4/9 of 3/5? well, is just their product, $\bf \cfrac{4}{9}\cdot \cfrac{3}{5}\implies \cfrac{12}{45}\implies \cfrac{4}{15}$

4 0

4 years ago

Read 2 more answers

1. Find the vertices and locate the foci for the hyperbola whose equation is given.

Irina18 [472]

$\bf \cfrac{(x-{{ h}})^2}{{{ a}}^2}-\cfrac{(y-{{ k}})^2}{{{ b}}^2}=1
\qquad center\ ({{ h}},{{ k}})\qquad
 vertices\ ({{ h}}\pm a, {{ k}})\\\\
-----------------------------\\\\
\textit{now let's take a look at yours}
\\\\\\
49x2 - 16y2 = 784\implies \cfrac{49x^2}{784}-\cfrac{16y^2}{784}=1
\\\\\\
\cfrac{x^2}{16}-\cfrac{y^2}{49}=1\implies \cfrac{(x-0)^2}{4^2}-\cfrac{(y-0)^2}{7^2}=1
\\\\\\
recall\implies center\ ({{ h}},{{ k}})\qquad vertices\ ({{ h}}\pm a, {{ k}})
\\\\\\
$

$\bf \textit{now, for the foci, the foci are "c" distance from the center point}\\\\\
whereas\qquad c=\sqrt{a^2+b^2}\qquad \textit{ that is }\qquad h\pm \sqrt{a^2+b^2}$

notice your "a" and "b" components, to get the distance "c" from the center to either foci and the vertices, of course, are h + a, k and h - a, k

5 0

3 years ago

Simplify (5b10)(−2b−3).

Angelina_Jolie [31]

Answer:

The answer is -10b11 -15b10

Step-by-step explanation:

8 0

3 years ago

What is the sum of the first eight terms of the series?

GenaCL600 [577]

The answer is -1195.31

3 0

3 years ago