There are no tens, ones, or tenths.
4,237,300.04
Personally I'd solve this inequality for y first: y < x-3.
That immediately eliminates (6,2) and (2,6).
Starting from y < x-3 and letting 2 sub for x and -1 sub for y, is the following true or false?
-1 < 2 -3 NO. -1 < -1 is false. Was there a fourth answer choice?
Answer:
108 = x
Step-by-step explanation:
multiple both sides by 24 and simplify
9 x 24 = 216/2=x
108 = x
Answer:
-4 and 4
Step-by-step explanation:
<u>Method 1</u>
Apply Difference of Two Squares Formula: ![a^2-b^2=(a+b)(a-b)](https://tex.z-dn.net/?f=a%5E2-b%5E2%3D%28a%2Bb%29%28a-b%29)
Given ![x^2-16=0](https://tex.z-dn.net/?f=x%5E2-16%3D0)
Rewrite 16 as 4²
Therefore,
and ![b^2=4^2](https://tex.z-dn.net/?f=b%5E2%3D4%5E2)
![\implies a = \sqrt{x^2}=x](https://tex.z-dn.net/?f=%5Cimplies%20a%20%3D%20%5Csqrt%7Bx%5E2%7D%3Dx)
![\implies b=\sqrt{4^2} =4](https://tex.z-dn.net/?f=%5Cimplies%20b%3D%5Csqrt%7B4%5E2%7D%20%3D4)
![\implies x^2-16^2=(x+4)(x-4)](https://tex.z-dn.net/?f=%5Cimplies%20x%5E2-16%5E2%3D%28x%2B4%29%28x-4%29)
![\implies (x+4)(x-4)=0](https://tex.z-dn.net/?f=%5Cimplies%20%28x%2B4%29%28x-4%29%3D0)
![\implies (x+4)=0 \implies x=-4](https://tex.z-dn.net/?f=%5Cimplies%20%28x%2B4%29%3D0%20%5Cimplies%20x%3D-4)
![\implies (x-4)=0 \implies x=4](https://tex.z-dn.net/?f=%5Cimplies%20%28x-4%29%3D0%20%5Cimplies%20x%3D4)
<u>Method 2</u>
Given equation:
![x^2-16=0](https://tex.z-dn.net/?f=x%5E2-16%3D0)
Add 16 to both sides:
![\implies x^2-16+16=0 + 16](https://tex.z-dn.net/?f=%5Cimplies%20x%5E2-16%2B16%3D0%20%2B%2016)
![\implies x^2=16](https://tex.z-dn.net/?f=%5Cimplies%20x%5E2%3D16)
Square root both sides:
![\implies \sqrt{x^2}=\sqrt{16}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csqrt%7Bx%5E2%7D%3D%5Csqrt%7B16%7D)
![\implies x=\pm4](https://tex.z-dn.net/?f=%5Cimplies%20x%3D%5Cpm4)
Therefore, x = -4, x = 4