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Drupady [299]
3 years ago
5

The model was shaded two different ways to show a product. Which product is shown by the model?The model was shaded two differen

t ways to show a product.
A fraction bar divided into 15 parts. 3 parts are shaded blue and 10 parts are shaded pink. 2 parts overlap.
Which product is shown by the model?

One-third × One-fifth
One-third × Two-fifths
Two-thirds × One-fifth
Two-thirds × Two-fifths
Mathematics
2 answers:
Lorico [155]3 years ago
7 0

Answer:

e

Step-by-step explanation:

9966 [12]3 years ago
6 0
If it’s ok for you can you put a picture of the question :)
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Lostsunrise [7]

Answer:

Inch to meters

meters = in x 0.0254

Step-by-step explanation:

5 0
3 years ago
What is the area of a rectangle whose length is 36 inches and whose width is 42 inches?
Alex

Answer:

1512

Step-by-step explanation:

L x W = Area

8 0
2 years ago
Solve by factorising<br><br><img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="abs
Paladinen [302]

Step-by-step explanation:

\underline{ \underline{ \text{Solving \: a \: quadratic \: equation \: by \: factorisation \: method}}} :

In this method , the second order of polynomial ax² + bx + c is factorised and expressed as the product of two linear factors. Then each linear factor is separately solved to get the required solutions of the equation by applying zero factor property. In zero factor property , if p•q = 0 , then either p = 0 or q = 0 . In other words , if the product of two numbers is 0 , then one or both of the numbers must be 0.

\underline{ \underline{ \text{Let's \: solve}}} :

\tt{ {x}^{2}  + 16x +  55 = 0}

Here , we have to find the two numbers that multiplies to 55 and adds to 16.

⤑ \tt{ {x}^{2}  + (11 + 5)x + 55 = 0}

⤑ \tt{ {x}^{2}  + 11x + 5x +  55 = 0}

⤑ \tt{x(x + 11) + 5(x + 11) = 0}

⤑ \tt{(x + 5)(x + 11) = 0}

Either :

\tt{x + 5 = 0 \: \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \: Or :  \:  \:  x + 11 = 0}

\sf{⟶ x  = 0 - 5} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    \:⟶  x =  0 - 11

\tt{⟶x =  - 5 } \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:     \:  \:⟶   x =  - 11

\red{ \boxed{ \boxed{ { \tt{Our \: final \: answer :  \boxed{ \underline{  \bold{ \tt{x  =  - 5 \: , - 11}}}}}}}}}

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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3 years ago
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6 0
3 years ago
Use the Pythagorean Theorem to find the length of the leg in the triangle shown below.
Natali [406]
The answer to what the length of the leg would be is 15.

You would do this problem by first writing down your Pythagorean Theorem, which is a^2 + b^2 = c^2.

Since we have our hypotenuse which is c^2 in our equation, we would write or insert the number we have.

So our equation could be that a or b leg equals 20, it doesn’t matter which one.

So we could write, 20^2 + b^2 = 25^2. So we don’t know what b leg is.

First we should figure out what 20^2 is and what 25^2 is.

20^2 is 400 and 25^2 is 625.

Our equation now comes to 400 + b^2 = 625.

Now we take 400 and subtract it from
625 -> 400 + b^2 = 625
-400.

So 625 - 400 comes out to be 225.

Lastly instead of squaring or putting 225 to the second power, we do the opposite.

So instead of squaring 225 we must square root 225. √ 225 .

The square root of √ 225 comes out to be 15.

3 0
3 years ago
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