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3 years ago

1+9i and 5-3i midpoint

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

6 0

Answer:

$3+3i$

Step-by-step explanation:

we know that

The formula to calculate the midpoint between two complex numbers (a+bi) and (c+di) points is equal to

$(\frac{a+c}{2})+(\frac{b+d}{2})i$

we have

(1+9i) and (5-3i)

substitute the given values

$(\frac{1+5}{2})+(\frac{9-3}{2})i$

$3+3i$

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Evaluate S5 for 300 + 150 + 75 + … and select the correct answer below. 18.75 93.75 581.25 145.3125

Savatey [412]

we have that

$300 + 150 + 75 +...$

Let

$a1=300\\ a2=150\\ a3=75$

we know that

$\frac{a2}{a1} =\frac{150}{300} \\\\ \frac{a2}{a1}=0.5 \\ \\ a2=a1*0.50$

$\frac{a3}{a2} =\frac{75}{150} \\\\ \frac{a3}{a2}=0.5 \\ \\ a3=a2*0.50$

$a(n+1)=an*0.50$

Is a geometric sequence

Find the value of $a4$

$a(4)=a3*0.50$

$a(4)=75*0.50$

$a(4)=37.5$

Find the value of $a5$

$a(5)=a4*0.50$

$a(5)=37.5*0.50$

$a(5)=18.75$

Find $S5$

$S5=a1+a2+a3+a4+a5\\ S5=300+150+75+37.5+18.75\\ S5=581.25$

therefore

the answer is

$581.25$

Alternative Method

Applying the formula

$S_n=\frac{a_1 (1-r^n)}{1-r} \\\\a_1=300 \\ r=\frac{1}{2}\\\\ S_5=\frac{300(1-(\frac{1}{2})^5)}{1-\frac{1}{2}}\\\\=\frac{300(1-\frac{1}{32})}{\frac{1}{2}}\\\\=\frac{300 \times \frac{31}{32}}{\frac{1}{2}}\\\\=\frac{75 \times \frac{31}{8}}{\frac{1}{2}}\\\\=\frac{\frac{2325}{8}}{\frac{1}{2}}\\\\=\frac{2325}{8} \times 2\\\\=\frac{2325}{4}\\\\=581 \frac{1}{4}\\\\=581.25$

therefore

the answer is

$581.25$

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Answer:

31.5 ft

Step-by-step explanation:

Use the Pythagorean Theorem

a² + b² = c²

Plug in the knowns

a² + 23² = 39²

Subtract 23² from both sides

a² = 39² - 23²

a² = 1521 - 529

a² = 992

Take the square root of both sides

a = 31.496031496

Rounded

a = 31.5 ft

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Martha Washington walks 30 minutes each day. If she walks for 140 days, how many hours will she walk?

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1+9i and 5-3i midpoint​

1+9i and 5-3i midpoint