All categories

3 years ago

Tell multiple ways to write 65% as a fraction

Mathematics

2 answers:

xxMikexx [17]3 years ago

8 0

65/100 or 13/20
Both work, it's just that 13/20 is simplified

elixir [45]3 years ago

4 0

60/100 or 65 over 100 which i can't make on my computer platform. Hope this helps.

You might be interested in

Solve (x+2<5) u (x-7>-6)

FrozenT [24]

Answer:

{x | x<3 or x>1}

Step-by-step explanation:

x+2<5

x<5-2

x< 3

x-7> -6

x> -6+7

x>1

symbol U means union

5 0

2 years ago

I need help pleaseeee

Lostsunrise [7]

Answer:A

Step-by-step explanation:

8 0

2 years ago

What is the area of this triangle ?

oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

$Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}$

We need to find the lengths of side DE, EF and FD

Length of side DE = a = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side DE = a = $=\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60$

Length of side EF = b = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side EF = b = $=\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8$

Length of side FD = c = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side FD = c = $=\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4$

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle= $=\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88$

So, area of triangle is 9.88 units^2

4 0

3 years ago

PLEASE HELP 50 POINTS

natima [27]

Answer:

C. 1/3<b<3/2

D. 1/6<x<2

Step-by-step explanation:

Hope this helps

3 0

2 years ago

Read 2 more answers

Whats the answer & how do I solve it ?

Veseljchak [2.6K]

Answer:

Area of rectangle = 225/2 or 112.5

Step-by-step explanation:

Given,

Consider a rectangle ABCD.

Let AC be a diagonal of rectangle of length = 15

In triangle ABC.

Sin 45° =height/hypotenuse {SinФ = height / hypotenuse}

Here, hypotenuse = diagonal of rectangle ( i.e AC = 15)

And height is AB

Therefore, sin 45° = AB/AC

or sin 45° = AB / 15

or 1/√2 = AB /15

AB = 15/√2

Similarly we can find Base (i.e BC) using cosine.

Cos 45° = Base/Hypotenuse

Cos 45° = BC / AC

or 1/√2 = BC/15

BC = 15/√2

Hence we got length of rectangle , AB= 15/√2

And width of rectangle , BC = 15/√2

Therefore, area of rectangle = Length × Width

Area of rectangle = 15/√2 × 15/√2 = 225/2

Hence, area of rectangle = 225/2 = 112.5

6 0

3 years ago