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Rufina [12.5K]
3 years ago
8

The perimeter of a rectangle is 86cm. Its shortest side has a length of 16cm. State the length of the longest side.

Mathematics
1 answer:
Artyom0805 [142]3 years ago
7 0

Answer: length = 27 cm

Step-by-step explanation:

Perimeter = 2(l + w)

86 = 2(l + 16)

86 = 2l + 32

86 - 32 = 2l

l = 54/2 = 27 cm.

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<span>The area of a square is (length of side)^2 , the perimeter of a square is 4*(length of side) 

Then your answer is 4 * sq rt (506.25 f`t^2) = 4 * 22.5 ft = 

= 90 ft of fence</span><span>Source(s):</span>
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3 years ago
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Solve.<br> f/5 - 24 = -28 <br><br> f =
jeka94

Answer:

f=260

Step-by-step explanation:

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Prepare a perpetual inventory​ record, using the FIFO inventory costing​ method, and determine the​ company's cost of goods​ sol
krek1111 [17]

Answer:

The First-In, First-Out (FIFO) inventory costing method assumes that the inventory items ordered first are the first ones sold.

Step-by-step explanation:

The First-In, First-Out inventory costing method assumes that the inventory items ordered first are the first sold. This is ideal for goods that are highly perishable, for example fresh milk. Since no figures or dates are given, we will assume that the month is March 2019 and use any figures to make the example.

Date Item      Quantity of stock Cost Price

01  Opening stock bought on Feb 28  10   100

05  Sale of 5 goods (cost is $10 each)  (5)   50

15 Purchase of stock (20 goods at $20 each) 20   400

25 Sale of 15 goods                     (15)   250  

(5 at $10 each & 10 at $20 each)

31 Closing Stock               10   200

       (20 goods bought on 15th - 10 goods sold on 25th)

The quantity on hand at the end of the month is 10 units.  

Total cost of goods on hand at end of the month = 10 units * $20 = 200.

Total cost of goods purchased during the month = $20 * 20 units = $400

Total cost of goods sold during the month = [($10 *5) + ($10 * 5)+ ($20 * 10)] = $200

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Point A(–4, 2) is reflected over the line x = 3 to create the point A'. What are the coordinates of A'?. . A. (–4, –1). B. (–4,
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5 0
3 years ago
A rectangular parking area measuring 5000 ft squared is to be enclosed on three sides using​ chain-link fencing that costs ​$5.5
kaheart [24]

Answer:

Dimensions: 75.3778 ft and 66.3325 ft

Minimum price: $1658.31

Step-by-step explanation:

Let's call the length of the parking area 'x', and the width 'y'.

Then, we can write the following equations:

-> Area of the park:

x * y = 5000

-> Price of the fences:

P = 2*x*5.5 + y*5.5 + y*7

P = 11*x + 12.5*y

From the first equation, we have that y = 5000/x

Using this value in the equation for P, we have:

P = 11*x + 12.5*5000/x = 11*x + 62500/x

To find the minimum of this function, we need to take its derivative and then make it equal to zero:

dP/dx = 11 - 62500/x^2 = 0

x^2 = 65000/11

x = 250/sqrt(11) = 75.3778 ft

This is the x value that gives the minimum cost.

Now, finding y and P, we have:

x*y = 5000

y = 5000/75.3778 = 66.3325

P = 11*x + 62500/x = $1658.31

5 0
3 years ago
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