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Ludmilka [50]
3 years ago
7

Which set(s) of points show x in DIRECT PROPORTION to y?

Mathematics
2 answers:
hodyreva [135]3 years ago
6 0

Answer:D){F, G, H} and {G, C, A} only

Step-by-step explanation:

vredina [299]3 years ago
5 0

Answer: OPTION D.

Step-by-step explanation:

For this exercise it is important to remember that:

1.  Direct proportion equations have the following form:

y=kx

Where "k" is the constant of proportionality.

2. The graph of Direct proportions is an straight line that passes through the origin.

Observe the picture attached.

If you join the points G, C and A, you get a straight line that passes through the origin,

If you join the points F, G and H, you also get a straight line that passes through the origin,

Therefore, the sets of points show "x" in Direct proportion to "y", are:

\{F, G, H\} and   \{{G, C, A}\}

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torisob [31]

ANSWER:

                 m∠1 = 60°

                 m∠2 = 60°

                 m∠3= 120°

EXPLANATION:

The purple arrows indicate that side are parallel, so we know that that triangle NMP is the same as triangle NOP. If they are they same then we know that ∠1 and ∠2 equal 60° since the opposing angles equal 60°.

For ∠3 we look at the opposing angle and now know it is 60°. Since ∠3 and the opposing angle make a straight line which equals 180°. We can figure out ∠3 by subtracting 60 from 180 = 120°.

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blagie [28]
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Step-by-step explanation:

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A water tank can be filled in 10 hours by an inlet pipe and empited in 14 hours by an outlet pipe.How long will it take to fill
zimovet [89]

t = amount of hours it takes to fill the tank.


let's say it takes "t" hours to do the whole tank, and we know the inlet pipe can do the whole tank in 10 hours, so, how much has it done in 1 hour only? well, since it takes 10 hours to do the whole tank, in 1 hour the inlet pipe has only done 1/10 of the whole job.


likewise, the outlet pipe can empty the whole thing in 14 hours, so how much has it emptied in 1 hour alone? well 1/14 of the whole tank.


keeping in mind both have done in 1 hour, only 1/t of the whole thing.


\bf \stackrel{\textit{total work done so far in 1 hour}}{\stackrel{\textit{inlet pipe's rate}}{\cfrac{1}{10}}~~-~~\stackrel{\textit{outlet pipe's rate}}{\cfrac{1}{14}}~~=~~\stackrel{\textit{work done}}{\cfrac{1}{t}}} \\\\\\ \cfrac{14-10}{140}=\cfrac{1}{t}\implies \cfrac{4}{140}=\cfrac{1}{t}\implies 4t=140\implies t=\cfrac{140}{4}\implies t=35

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Sati [7]
Answer is d (the last one)

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