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gregori [183]
2 years ago
9

Someone please help me I’m failing

Mathematics
2 answers:
Amanda [17]2 years ago
8 0

Answer:

1. x>3

2.x>-2

3.x<-3

4.x<2

hope u dont fail

mash [69]2 years ago
5 0

Answer:

1. x > 3

2. x > -2

3. x < -3

4. x < 2

Step-by-step explanation:

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A mass of 1 g is set in motion from its equilibrium position with an initial velocity of 6in/sec, with no damping and a spring c
yan [13]

a) y(t)=0.0016 sin(94.9t) [m]

b) 0.033 s

c) -0.152 m/s

Step-by-step explanation:

a)

The force acting on the mass-spring system is (restoring force)

F=-ky

where

k = 9 is the spring constant

y is the displacement

Also, from Newton's second law of motion, we know that

F=my''

where

m = 1 g = 0.001 kg is the mass

y'' is the acceleration

Combining the two equations,

my''=-ky

This is a second order differential equation; the solution for y(t) is

y(t)=A sin(\omega t-\phi)

where

A is the amplitude of motion

\omega=\sqrt{\frac{k}{m}}=\sqrt{\frac{9}{0.001}}=94.9 rad/s is the angular frequency

The spring starts its motion from its equilibrium position, this means that y=0 when t=0; therefore, the phase shift must be

\phi=0

So the displacement is

y(t)=A sin(\omega t)

The velocity of the spring is equal to the derivative of the displacement:

v(t)=y'(t)=\omega A cos(\omega t)

We know that at t = 0, the initial velocity is 6 in/s; since 1 in = 2.54 cm = 0.0254 m,

v_0=6(0.0254)=0.152 m/s

And since at t = 0, cos(\omega t)=1

Then we have:

v_0=\omega A

From which we find the amplitude:

A=\frac{v_0}{\omega}=\frac{0.152}{94.9}=0.0016 m

So the solution for the displacement is

y(t)=0.0016 sin(94.9t) [m]

b)

Here we want to find the time t at which the mass returns to equilibrium, so the time t at which

y=0

This means that

sin(\omega t)=0

We know already that the first time at which this occurs is

t = 0

Which is the beginning of the motion.

The next occurence of y = 0 is instead when

\omega t = \pi

which means:

t=\frac{\pi}{\omega}=\frac{\pi}{94.9}=0.033 s

c)

As said in part a), the velocity of the mass-spring system at time t is given by the derivative of the displacement, so

v(t)=\omega A cos(\omega t)

where we have

\omega=94.9 rad/s is the angular frequency

A=0.0016 m is the amplitude of motion

t is the time

Here we want to find the velocity of the mass when the time is that calculated in part b):

t = 0.033 s

Substituting into the equation, we find:

v(0.033)=(94.9)(0.0016)cos(94.9\cdot 0.033)=-0.152 m/s

4 0
3 years ago
What is the slope to this one? Will give brainliest
Mademuasel [1]

Answer:

Negative Slope.

-7/5

Step-by-step explanation:

Decreasing from left to right.

x = 3- -2 = 5

y = -2 - 5 = -7

y = -7/5x + 11/5

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2 years ago
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Trevor says the figure B is a scaled copy of figure 8 because figure B is three times larger than figure A
yanalaym [24]

Answer:

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Step-by-step explanation:

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3 years ago
I need help i dont understand how to do this!!​
Schach [20]

Answer:

16, see below :)

Step-by-step explanation:

Hello!

We can use the pythagorean theorem because one of the angles is 90 degrees. According to the theorem, a^2 + b^2 = c^2

a is 12, b is unknown, and c is 20

Now we use the theorem

12^2 + b^2 = 20^2

144 + b^2 = 400

b^2 = 256

b = sqrt(256)

b = 16

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2 years ago
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11) Wayne exercised for 5/6 of an hour in the morning and 1/3 of an hour in the evening. How much more of an hour did Wayne spen
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He spent 3/6 hours more or 30 minutes more
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