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Feliz [49]
3 years ago
12

James drove 6 miles south and then 3 miles west.how far is he from his starting point

Mathematics
1 answer:
Minchanka [31]3 years ago
7 0

Answer:

9 miles

Step-by-step explanation:

A 6+3 is nine

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myrzilka [38]
100/9 good luck this should be right

5 0
2 years ago
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The profit when selling 'x' pairs of shoes is P(x)=-4x^2+32x-39. How many pairs of shoes should be sold in order to maximize the
Vitek1552 [10]

Answer: 4 pairs

Step-by-step explanation:

Given

Profit on selling 'x' pairs of shoes is P(x)=-4x^2+32x-39

Find the derivative of the function to find out the critical points

\Rightarrow -8x+32=0\\\Rightarrow x=4

Thus, for 4 pair of shoes profit is maximize.

5 0
3 years ago
A physical education teacher wanted to test whether her county’s students are falling below the national proportion. It is known
Ipatiy [6.2K]

Answer:

(a) The population parameter is students who ran the mile in less than 10 minutes.

(b) The hypothesis being tested is:

H0: p = 0.70

Ha: p < 0.70

(c) The significance level is 0.05.

(d) In order to conduct a one-sample proportion z-test, the following conditions should be met:

The data are a simple random sample from the population of interest.

The population is at least 10 times as large as the sample.

n⋅p ≥ 10 and n⋅(1−p) ≥ 10, where n is the sample size and p is the true population proportion.

n⋅p = 756 * 0.70 ≥ 10

n⋅(1−p) = 756 * (1 - 0.70) ≥ 10

All the conditions are met.

(e) p = 504/756 = 0.67

The test statistic, z = (p - p)/√p(1-p)/n = (0.67 - 0.70)/√0.70(1-0.70)/756 = -2.00

(f) The p-value is 0.0228.

(g) Since the p-value (0.0228) is less than the significance level (0.05), we can reject the null hypothesis.

(h) Therefore, we can conclude that less than 70% of students run one mile in less than 10 minutes.

Step-by-step explanation:

7 0
3 years ago
A school is planning to construct two rectangular play areas in the playground. The length of play area A must be 1 foot longer
Anna11 [10]

Answer:

А.The system has two solutions, but only one is viable because the other results in a negative width.

Step-by-step explanation:

Given

Let:

L_A \to length of play area A

W_A \to width of play area A

L_B \to length of play area B

W_B \to width of play area B

x \to Area of A

y \to Area of B

From the question, we have the following:

L_A = 1 + 4W_A

W_B = 2 + W_A

L_B = 2 + 3W_B

x = y

The area of A is:

x = L_A * W_A

This gives:

x = (1 + 4W_A) * W_A

Open bracket

x = W_A + 4W_A^2

The area of B is:

y = L_B * W_B

y = (2 + 3W_B) * ( 2 + W_A)

Substitute: W_B = 2 + W_A

y = (2 + 3(2 + W_A)) * ( 2 + W_A)

Open brackets

y = (2 + 6 + 3W_A) * ( 2 + W_A)

y = (8 + 3W_A) * ( 2 + W_A)

Expand

y = 16 + 8W_A + 6W_A + 3W_A^2

y = 16 + 14W_A + 3W_A^2

We have that:

x = y

This gives:

W_A + 4W_A^2 = 16 + 14W_A + 3W_A^2

Collect like terms

4W_A^2 - 3W_A^2 + W_A  -14W_A  - 16 =0

W_A^2  -13W_A  - 16 =0

Using quadratic calculator, we have:

W_A = -14.1 or W = 1.13 --- approximated

But the width can not be negative; So:

W = 1.19

7 0
3 years ago
What is the measure of the indicated arc in radians?
iogann1982 [59]

Answer:

D is the right one

Step-by-step explanation:

π radian = 180 degree

-> 135 degree = \frac{135}{180} π radian

-> 135 degree = 0.75 * π  radians = 3π/4 radian

5 0
3 years ago
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