Dimensions of the room in cm = 2.54 x 12 by 15 x 2.54 by 2.54 x 8.5 = 30.48 by 38.1 by 21.59
Volume of the room in cubic cm = 30.48 x 38.1 x 21.59 cubic cm = 25,072.21 cubic cm
Given that the density of air at room temperature is
![0.00118g/cm^3](https://tex.z-dn.net/?f=0.00118g%2Fcm%5E3)
, thus the mass of air in the room = 25,072.21 x 0.00118 = 29.59 g = 0.0296 kg
Given that the lethal dose of HCN is approximately 300 mg HCN per kilogram of air when inhaled, thus the <span>amount of HCN that gives the lethal dose in the small laboratory room is given by 300 x 0.0296 =
8.88 mg.</span>
Answer:
- Perimeter = 22*sqrt(2)
- Area = 60.5 inches
- D
Step-by-step explanation:
Remark
You need 2 facts.
- A square has 4 equal sides.
- It contains (by definition) 1 right angle but since we are not including and statement about parallel sides, it needs 4 right angles.
That means you can use the Pythagorean Theorem.
If one side of a square is a then the 1 after it is a as well.
Formula
- a^2 + a^2 = c^2
- 2a^2 = c^2
Givens
Solution
- 2a^2 = 11^2
- 2a^2 = 121 Divide by 2
- a^2 = 121/2 Take the square root of both sides
- sqrt(a^2) = sqr(121/2)
- a = 11/sqrt(2) Rationalize the denominator
- a = 11 * sqrt(2)/[sqrt(2) * sqrt(2)]
- a = 11 * sqrt(2) / 2
<em><u>Perimeter</u></em>
P = 4s
- P = 4*11*sqrt(2)/2
- P = 44*sqrt(2)/2
- P = 22*sqrt(2)
You don't need the area. The answer is D
<em><u>Area</u></em>
- Area = s^2
- Area = (11*sqrt(2)/2 ) ^2
- Area = 121 * 2 / 4
- Area = 60.5
For this case we have to:
x: Let the variable representing the number of people to travel in the group
y: Let the variable representing the number of miles traveled.
If friends only have $22 then we have the following inequality:
![2.50x + 0.75y \leq22](https://tex.z-dn.net/?f=2.50x%20%2B%200.75y%20%5Cleq22)
Now, if there are three people in the group we have that ![x = 3.](https://tex.z-dn.net/?f=x%20%3D%203.)
![2.50 (3) + 0.75y \leq22\\7.5 + 0.75y \leq22\\0.75y \leq22-7.5\\0.75y \leq14.5\\y\leq \frac {14.5} {0.75}\\y\leq19.33](https://tex.z-dn.net/?f=2.50%20%283%29%20%2B%200.75y%20%5Cleq22%5C%5C7.5%20%2B%200.75y%20%5Cleq22%5C%5C0.75y%20%5Cleq22-7.5%5C%5C0.75y%20%5Cleq14.5%5C%5Cy%5Cleq%20%5Cfrac%20%7B14.5%7D%20%7B0.75%7D%5C%5Cy%5Cleq19.33)
The taxi can travel a maximum of 19.33 miles.
On the other hand, if the group wants to travel 10 miles then we have to y = 10.
![2.50x + 0.75 (10) \leq22\\2.50x + 7.5 \leq22\\2.50x \leq22-7.5\\2.50x \leq14.5\\x\leq \frac {14.5} {2.50}\\x \leq5.8](https://tex.z-dn.net/?f=2.50x%20%2B%200.75%20%2810%29%20%5Cleq22%5C%5C2.50x%20%2B%207.5%20%5Cleq22%5C%5C2.50x%20%5Cleq22-7.5%5C%5C2.50x%20%5Cleq14.5%5C%5Cx%5Cleq%20%5Cfrac%20%7B14.5%7D%20%7B2.50%7D%5C%5Cx%20%5Cleq5.8)
Thus, they could travel a maximum of 5 people.
ANswer:
![2.50x + 0.75y \leq22](https://tex.z-dn.net/?f=2.50x%20%2B%200.75y%20%5Cleq22)
Traveling 3 people, the taxi can travel a maximum of 19.33 miles
Traveling 10 miles, a maximum of 5 people can travel
7-3=4
4/2=2
The answer is 2