Answer:
Distance from the airport = 894.43 km
Step-by-step explanation:
Displacement and Velocity
The velocity of an object assumed as constant in time can be computed as
Where is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as
The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as
The displacement of the plane in 2 hours is
Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are
The displacement in 1 hour is
The total displacement is the vector sum of both
The distance from the airport is the module of the displacement:
Answer:
y = 4,-6
Step-by-step explanation:
0 property states that 0 times any number is 0
applying that here, that means y+6 = 0 or y-4 = 0
0(y-4) = 0; (y+6)(0) = 0
y+ 6 = 0
y = -6
y-4 = 0
y = 4
Answer:A = P(1+r/n)nt
A = 3500(1+.092/4)4t
Step-by-step explanation:
Answer:
B. -255
Step-by-step explanation:
This picture is from the user of: DBlaze.
The solution to given system of equation is (x, y) = (0.8, 2.2)
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
y + x = 3 --------- eqn 1
y = 1.5x + 1 ---------- eqn 2
We have to solve the above system of equations by substitution method
<em><u>Substitute eqn 2 in eqn 1</u></em>
1.5x + 1 + x = 3
Combine the like terms
2.5x + 1 = 3
Move the constants to Right hand side of equation
2.5x = 3 - 1
2.5x = 2
x = 0.8
<em><u>Substitute x = 0.8 in eqn 2</u></em>
y = 1.5(0.8) + 1
y = 1.2 + 1
y = 2.2
Thus the solution to given system of equation is (x, y) = (0.8, 2.2)