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7nadin3 [17]
3 years ago
11

Solve for a.

Mathematics
2 answers:
FinnZ [79.3K]3 years ago
8 0

Answer:

iii) a=3b/2

Step-by-step explanation:

7a-2b= 5a+b

7a-5a=2b+b

2a=3b

a=3b/2

pychu [463]3 years ago
8 0

Answer:

\large\boxed{a=\dfrac{3b}{2}=\dfrac{3}{2}b=1.5b}

Step-by-step explanation:

7a-2b=5a+b\qquad\text{add}\ 2b\ \text{to both sides}\\\\7a-2b+2b=5a+b+2b\\\\7a=5a+3b\qquad\text{subtract}\ 5a\ \text{from both sides}\\\\7a-5a=5a-5a+3b\\\\2a=3b\qquad\text{divide both sides by 2}\\\\\dfrac{2a}{2}=\dfrac{3b}{2}\\\\a=\dfrac{3b}{2}

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Solve the system of equations 4x+5y=-1 and -5x-8y=10 by combining the equations.
Nimfa-mama [501]

The solution of the equation are as follows:

x = 6 and y = -5

<h3 />

<h3>How to solve the system of equation?</h3>

4x + 5y = -1

-5x - 8y = 10

Therefore,

20x + 25y = -5

-20x - 32y = 40

-7y = 35

y = -5

Hence,

4x + 5(-5) = -1

4x - 25 = -1

4x = -1 + 25

4x = 24

x = 24 / 4

x = 6

learn more on equation here:brainly.com/question/14383993

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6 0
1 year ago
8+a=21 plssssssssssssszzzz​
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Answer:

13

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3 years ago
How do you solve a table of equivalent ratios
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2 years ago
Which are solutions of the equation x2 - 16 = 0? Check all that apply.
Setler [38]

Answer:

x=-4

x=4

Step-by-step explanation:

We can factor x^2 -16 = 0 by recognizing that it is a difference of squares. That means we can factor the equation to (x-4)(x+4) = 0. By using the Zero Product Property we know that either (x-4) or (x+4) is equal to 0. That means that x either equals -4 or 4.

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Which expression is equivalent to the expression below? StartFraction 6 c squared 3 c Over negative 4 c 2 EndFraction divided by
Fudgin [204]

The given equation (6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2) is equivalent to the expression -3c.

Given that, the expression can be written as.

(6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)

By simplifying the above equation,

\dfrac{6c^2+3c}{-4c+2}\div \dfrac{2c+1}{4c-2}

By taking out the common terms from the equation,

\dfrac{3c(2c+1)}{2(-2c+1)}\div\dfrac{2c+1}{2(2c-1)}

By simplifying the above equation by cancel out the common factors.

\dfrac{3c}{-2c+1} \div \dfrac{1}{2c-1}

Now, by taking (-1) common from (-2c+1) we get,

\dfrac{3c}{-1(2c-1)} \div \dfrac{1}{2c-1}

By simplifying the above equation, we get the expression,

-3c

So the given equation (6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2) is equivalent to the expression -3c.

For more details, follow the link given below.

brainly.com/question/1301963.

7 0
2 years ago
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