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Law Incorporation [45]
3 years ago
9

Which category of two-dimensional shapes applies to all three of these shapes?

Mathematics
2 answers:
snow_tiger [21]3 years ago
8 0
A (scalene) because a scalene triangle is a triangle that has all sides with a different angle measure
prohojiy [21]3 years ago
5 0
The answer you are looking for is A. Scalene
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Thx and have a great day!!
Elan Coil [88]

Answer:A

Step-by-step explanation:<3and <11 are corresponding angles, and corresponding angles are congruent

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2 years ago
What is the surface area of the square pyramid represented by the net?
Illusion [34]
Would need the net to answer. but to find the answer you need to find the slant height of the square pyramid, the slant height is the hypotenuse of the right triangle formed by the height and half the base length. Use the pythagorean Theorem
7 0
3 years ago
At a digital store, Jay paid a total of $31.35 for games and movie rental. He rented 6 games at $3.99 each game and 3 movies.
dmitriy555 [2]

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Step-by-step explanation:

cuz i have the same homework

3 0
2 years ago
While shopping, janet bought a shirt for $8, a pair of jeans for $22, mittens for $5, and a hat for $10. how much money did jane
Talja [164]
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5 0
3 years ago
A quadratic equation is shown below:
Valentin [98]
Part A)

The given equation is:

25 x^{2} +10x+1=0

The radicand or discriminant(d) of the equation will be:

d=(10)^{2}-4(25)(1) \\  \\ &#10;d=100-100 \\  \\ &#10;d=0

Since the discriminant is equal to 0, the given quadratic equation has only 1 root. In other words we can say the the given equation is a perfect square. 


Part B)

The given equation is:

4 x^{2} -4x+1=0

We can solve this expression by factorization. Factors of middle term are to be made in such a way that their product equals the product of first and third term and sum is equal to the middle term i.e. product should be 4x² and sum should be -4x.
So the two such terms are -2x and -2x. Using the factors and simplifying the equation by taking common we get:

4 x^{2} -2x-2x+1=0 \\  \\ &#10;2x(2x-1)-1(2x-1)=0 \\  \\ &#10;(2x-1)(2x-1)=0 \\  \\ &#10;(2x-1) ^{2}=0 \\  \\ &#10;2x-1=0  \\  \\ &#10;x= \frac{1}{2}
4 0
3 years ago
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