Answer:
Answers bolded below
Step-by-step explanation:
PAGE 1
20.) 142 + 24 + 2x - 50 = 180 (collect like terms)
116 + 2x = 180 (subtract 116 on both sides)
2x = 64 (divide by 2x on both sides)
x = 32
21.) 40 + 80 + 5m = 180 (collect L.T.'s)
120 + 5m = 180 (subtract 120 on both sides)
5m = 60 (divide by 5 on both sides)
m = 12
PAGE 2
10.) <T
11.) CA
12.) ^CAB
13.) UV
14.) m<A = m<T = 66
15.) B, C, A
PAGE 3
16.) ^BAD = ^DCB
17.) ^GFH = ^KJH
18.) x = 7 and y = 8
10x + 65 = 135
10x = 70
x = 7
4y - 4 = 28
4y = 32
y = 8
19.) b = 13 and n = 13
5b - 3 = 62
5b = 65
b = 13
4n - 4 = 48
4n = 52
n = 13
PAGE 4
1.) <A = <D, <B = <E, <C = <F
2.) AB = DE, CB = FE, FD = CA
3.) CAB = FDE, EFD = BCA, BAC = EDF
4.) m<P =105
5.) m<M = 45
6.) m<R = 30
7.) m<N = 30
8.) QR = MN
9.) LN = PR
Hope this helps ya!!
So what you do is simple it is only one year that you are getting the 16% so how to solve is this way: $4500 + 16%= $5220
Answer:
P (X<120)=0
Step-by-step explanation:
We can compute the probability for women:
μ=259 and σ=32
P ( X<120 )=P ( X−μ<120-259 )=P ((X−μ)/σ<(120−259)/32)
Since (x−μ)/σ =Z
and
we have:
Use the standard normal table to find this area.
Now we can find P ( Z<4.34 ) by using the standard normal table which is 1:
Therefore: P (X<120)=0
For men
μ=242 and σ=29
P ( X<120 )=P ( X−μ<120-242 )=P ((X-μ)/σ <(120-242)/29 )
Since (x-μ)/σ=Z
and
we have:
Use the standard normal table to find this area.
Now we can find P ( Z<4.21 ) by using the standard normal table which is 1:
Therefore: P (X<120)=0
My best estimate for this figure is 15