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NikAS [45]
3 years ago
8

Replace? with =, >, or < to make the statement true. 16 ÷ 4 + 12? 4 + 24 ÷ 2

Mathematics
1 answer:
AleksAgata [21]3 years ago
6 0
<em><u>16/4+12 ? 24/2</u></em>
<em><u>4+12 ? 12</u></em>
<em><u>16 ? 12</u></em>
<em><u>?=></u></em>

<em><u>ANSWER: A - ></u></em>
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Effectus [21]
Consider posting each question separately, please.

Given   <span>-2.8k-4.31=-15.79 :

1) Isolate the "k" term on the left by adding 4.31 to both sides of this equation.
2) Simplify the right side.
3) Divide both sides by -2.8 and you'll have the answer:  k = ?</span>
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3 years ago
In the diagram, which two angles are corresponding angles with angle 12?
Rama09 [41]

Answer:

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Step-by-step explanation:

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Simple geometry please help<br><br> Find KL. Round to the nearest hundredth.
vivado [14]

Answer:

KL ≈ 1.94

Step-by-step explanation:

Using the cosine ratio in the right triangle

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Scilla [17]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
If a snowball melts so that its surface area decreases at a rate of 9 cm2/min, find the rate (in cm/min) at which the diameter d
zhuklara [117]

Answer:

The diameter decreases at a rate of 0.143cm/min when it is of 10 cm.

Step-by-step explanation:

Surface area of an snowball:

An snowball has spherical format. The surface area of an sphere is given by:

S = d^2\pi

In which d is the diameter of the sphere.

In this question:

We need to differentiate S implicitly in function of time. So

\frac{dS}{dt} = 2d\pi\frac{dd}{dt}

Surface area decreases at a rate of 9 cm2/min

This means that \frac{dS}{dt} = -9

At which the diameter decreases when the diameter is 10 cm?

This is \frac{dd}{dt} when d = 10. So

\frac{dS}{dt} = 2d\pi\frac{dd}{dt}

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\frac{dd}{dt} = -\frac{9}{20\pi}

\frac{dd}{dt} = -0.143

Area in cm², so diameter in cm.

The diameter decreases at a rate of 0.143cm/min when it is of 10 cm.

8 0
3 years ago
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