Answer:
Given : JKLM is a rectangle.
Prove: JL ≅ MK
Since, by the definition of rectangle all angles of rectangles are right angle.
Thus, In rectangle JKLM,
∠ JML and ∠KLM are right angles.
⇒ ∠ JML ≅ ∠KLM
Since, JM ≅ KL (Opposite sides of rectangles are congruent)
ML ≅ ML ( Reflexive )
Thus, By SAS congruence postulate,
Δ JML ≅ Δ KLM
⇒ JL ≅ MK ( because corresponding parts of congruent triangles are congruent)
Hence proved.
Answer:
B
Step-by-step explanation:
Given
P = 2(l + b) ← distribute
P = 2l + 2b ( subtract 2b from both sides )
P - 2b = 2l ( divide both sides by 2 )
= l → B
Answer:
Third option given
Step-by-step explanation:
On a coordinate plane, a parabola opens to the right with a vertex at (0, 0).
use the following x values to plot the associated y values on the x-y plane:
If x = 0, then
If x = 1, then
If x = 4, then
If x = 9, then
Join the points and you will find a branch of a parabola opening to the right.