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3 years ago

13

When a number, n, is increased by two and then the result is divided by five the quotient is equal to 14. write an equation and

solve it to find the value of n.
NEED STEP BY STEP EXPLANATION

1 answer:

zavuch27 [327]3 years ago

3 0

Step-by-step explanation:

We have (n + 2)/5 = 14.

=> (n + 2) = 14 * 5 = 70 (multiply 5 on both sides)

=> n = 70 - 2 = 68. (subtract 2 on both sides)

Hence the number n is 68.

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It's a rotation clockwise of 90 degrees about the origin.

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The given point moves from y = 5 to x = 5 so it has passed through 90 degrees about the origin.

It's a rotation clockwise of 90 degrees about the origin.

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3 years ago

Consider the question of whether the home team wins more than half of its games in the National Basketball Association. Suppose

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0.0037 = 0.37% probability that the home team would win 65% or more of its games in a simple random sample of 80 games

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

The home team therefore wins 50% of its games

This means that $p = 0.5$

Determine the probability that the home team would win 65% or more of its games in a simple random sample of 80 games

Sample of 80 means that $n = 80$ and, by the Central Limit Theorem:

$\mu = p = 0.65$

$s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.5*0.5}{80}} = 0.0559$

This probability is 1 subtracted by the pvalue of Z when X = 0.65. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.65 - 0.5}{0.0559}$

$Z = 2.68$

$Z = 2.68$ has a pvalue of 0.9963

1 - 0.9963 = 0.0037

0.0037 = 0.37% probability that the home team would win 65% or more of its games in a simple random sample of 80 games

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Step-by-step explanation:

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2 years ago

Please help me and if you need help with any questions i will return thank ya

Charra [1.4K]

Step two is the answer i hope that helps

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3 years ago

Read 2 more answers