It should be 8 if I’m not mistaken
Let the numbers be:
a, a+b, a+2b
mean of the numbers is:
(a+a+b+a+2b)/3=10
(3a+3b)/3=10
a+b=10
thus second term is 10
The sum of square will be:
((10 - b)² + 10² + (10 + b)²<span>) / 3 = 394
</span>(100 - 20b + b² + 100 + 100 + 20b + b²<span>) / 3 = 394
</span><span>(300 + 2b</span>²<span>) / 3 = 394
</span>(150+b²)=591
b²=441
b=-21,21
thus the numbers will be:
10-21, 10, 10+21
=-11,10,31
Answer: 35p+65
Step-by-step explanation: Distribute the 5 to the 7p and 13.
5x7p=35p
5x13=65
Add these together to get 35p+65.
