Answer:
Step-by-step explanation:
Move 729  to the left side of the equation by subtracting it from both sides.  x  3 − 729  = 0  Factor the left side of the equation.  Rewrite  729  as 9
3
.  x
3
−
9
3
=
0
. Since both terms are perfect cubes, factor using the difference of cubes formula,  a
3
−
b
3
=
(
a
−
b
)
(
a
2+ab+b2). Where a
=x and  b=9. (x−9)(x2+x⋅9+92)=0
. Simplify.  Move 9  to the left of x
.  (x−9)(x2+9x+92)=0.  Raise  9  to the power of 2
.  (x
−9
)(
x
2
+
9
x
+81
)=0
. Set x
−9  equal to  0 and solve for x.  Set the factor equal to  0. x−
9=
0. Add 9  to both sides of the equation.  x=9
. Set x2+
9
x
+
81 equal to  0  and solve for  x
.  Set the factor equal to 0
.  x2+9x+81=0.  Use the quadratic formula to find the solutions.  −b±√b2−4(ac) 2a. Substitute the values  a=1, b=9, and c=81  into the quadratic formula and solve for  x.  −9±√92−4⋅ (1⋅81
) 2⋅
1  Simplify.  Simplify the numerator. Raise 9  to the power of 2. x=−9±√81−4⋅(1⋅81) 2⋅1. Multiply  
81
 by  
1
.
x
=
−
9
±
√
81
−
4
⋅
81
2
⋅
1
Multiply  
−
4
 by  
81
.
x
=
−
9
±
√
81
−
324
2
⋅
1
Subtract  
324
 from  
81
.
x
=
−
9
±
√
−
243
2
⋅
1
Rewrite  
−
243
 as  
−
1
(
243
)
.
x
=
−
9
±
√
−
1
⋅
243
2
⋅
1
Rewrite  
√
−
1
(
243
)
 as  
√
−
1
⋅
√
243
.
x
=
−
9
±
√
−
1
⋅
√
243
2
⋅
1
Rewrite  
√
−
1
 as  
i
.
x
=
−
9
±
i
⋅
√
243
2
⋅
1
Rewrite  
243
 as  
9
2
⋅
3
.
Tap for fewer steps...
Factor  
81
 out of  
243
.
x
=
−
9
±
i
⋅
√
81
(
3
)
2
⋅
1
Rewrite  
81
 as  
9
2
.
x
=
−
9
±
i
⋅
√
9
2
⋅
3
2
⋅
1
Pull terms out from under the radical.
x
=
−
9
±
i
⋅
(
9
√
3
)
2
⋅
1
Move  
9
 to the left of  
i
.
x
=
−
9
±
9
i
√
3
2
⋅
1
Multiply  
2
 by  
1
.
x
=
−
9
±
9
i
√
3
2
Factor  
−
1
 out of  
−
9
±
9
i
√
3
.
x
=
−
1
9
±
9
i
√
3
2
Multiply  
−
1
 by  
−
1
.
x
=
1
−
9
±
9
i
√
3
2
Multiply  
−
9
±
9
i
√
3
 by  
1
.
x
=
−
9
±
9
i
√
3
2
The final answer is the combination of both solutions.
x
=
−
9
−
9
i
√
3
2
,
−
9
+
9
i
√
3
2
The solution is the result of  
x
−
9
=
0
 and  
x
2
+
9
x
+
81
=
0
.
x
=
9
,
−
9
−
9
i
√
3
2
,
−
9
+
i
√
3
2