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3 years ago

What is the value of the rational expression 3-x/x-6 when x is equal to 9?

Mathematics

1 answer:

yKpoI14uk [10]3 years ago

7 0

Answer:

$\boxed{\sf \ \ \ answer \ \ B \ \ \ }$

Step-by-step explanation:

Hello,

x is like a container, it can contain any real number

in that case we need to replace x by 9

so we need to compute the following

$\dfrac{3-x}{x-6} \ for \ x =9\\\dfrac{3-9}{9-6}=\dfrac{-6}{3}=-2$

so the winner is the answer B

hope this helps

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3 years ago

How do u write 3:4 and 6:8 as a fraction proportion

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3 years ago

Read 2 more answers

Solve by using substitution.<br><br> =3−8<br><br> =−4

garik1379 [7]

Answer:

I'm going to assume that you meant y=3x-8 and y=-4

This means that you would substitute -4 into the spot of y which gives you -4=3x-8. Once solved you would receive x=4/3.

Hope I helped have a nice day :)

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3 years ago

In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b

madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding $(ax+by)^7$ using Binomial expansion, we have that:

$(ax+by)^7$ =

$(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7$

$= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7$