Let O be the point of intersection of diagonals.
Consider triangles FOE and EOD:
FO = OD, ∠FOE = ∠EOD and OE is a common side ⇒
triangles FOE and EOD are congruent.
In congruent triangles all corresponding sides and are congruent ⇒
EF = DE = 6
Answer:
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Step-by-step explanation:
The answer to the question is ORTHOCENTER. The altitude is the line that connects the vertex of a triangle to the opposite side making a 90 degrees with it. Thus, the use of the prefix ortho- for the points where the three altitudes meet.
Hey, you didn’t add the options or following expressions. Can you add them in the comments so I can try and help you out?
Answer:
y=-1/2x-8
Step-by-step explanation:
m=(y2-y1)/(x2-x1)=(-6-(-5))/(-4-(-6))=(-6+5)/(-4+6)=-1/2
slope is -1/2
y-y1=m(x-x1) where m=slope
y-(-5)=-1/2(x-(-6))
y+5=-1/2(x+6)
y=-1/2x-6/2-5
y=-1/2x-3-5
y=-1/2x-8
