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Alinara [238K]
3 years ago
10

NEED HELP ASAP PLS AND THANK YOU!!!!

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
8 0

Answer:

Step-by-step explanation:

Urgent urgent urgent urgent

You're urgent

marysya [2.9K]3 years ago
8 0
Not sure but think it’s the last one
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PLEASE HELP FAST I NEED A EXPERT OR ABOVE I WILL GVOE YOU ALOT OF POINTS!
kicyunya [14]

Answer:

547.5 cm

Step-by-step explanation:

730(9/12)=547.5

7 0
2 years ago
Is 200% a whole number​
zimovet [89]

Answer:

Yes

Step-by-step explanation:

200% is basically 2/1, and 2/1 = 2. 2 is a whole number.

7 0
3 years ago
Esther's company has been contracted to lay carpet in a room at a new observatory. The floor plan for the room is in the shape o
timofeeve [1]

Answer:

  • 3960 ft²

Step-by-step explanation:

The pentagon has been split into 5 congruent triangles.

<u>Each triangle has area of:</u>

  • 1/2*48*\sqrt{40.8^2 - (48/2)^2} = 24*\sqrt{1088.64} = 24*33 = 792 ft²

<u>The area of the room is:</u>

  • 792*5 = 3960 ft²

5 0
2 years ago
How can csc^2-cot^2 = 1?
Softa [21]

ANSWER

By simplifying the left hand side using the Pythagorean Identity.

EXPLANATION

The given identity is

\csc^{2} (x) -  \cot^{2} (x) = 1

Take the left hand side and simplify to get the right hand side.

\csc^{2} (x) -  \cot^{2} (x) =  \frac{1}{\sin^{2} (x)}  - \frac{ \cos^{2} (x)}{\sin^{2} (x)}

Collect LCM for the denominators.

\csc^{2} (x) -  \cot^{2} (x) =  \frac{1 -  \cos^{2} (x)}{\sin^{2} (x)}

Recall the Pythagorean Identity.

\cos^{2} (x) +  \sin^{2} (x) = 1

This implies that:

1 -  \cos^{2} (x) =  \sin^{2} (x)

We substitute this to get,

\csc^{2} (x) -  \cot^{2} (x) =  \frac{\sin^{2} (x)}{\sin^{2} (x)}

\csc^{2} (x) -  \cot^{2} (x) = 1

6 0
3 years ago
If one of the sides of the regular polygon pictured has a side length of 3x+2, what is the length of all the sides
leonid [27]

Answer:

3x+2

Step-by-step explanation:

The polygon is regular ,<em> </em>so all the sides would be equal.

Thus all sides measure same as <u>3x</u><u>+</u><u>2</u>

7 0
3 years ago
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