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3 years ago

NEED HELP ASAP PLS AND THANK YOU!!!!

Mathematics

2 answers:

Liono4ka [1.6K]3 years ago

8 0

Answer:

Step-by-step explanation:

Urgent urgent urgent urgent

You're urgent

marysya [2.9K]3 years ago

8 0

Not sure but think it’s the last one

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Write an explicit formula for an, the nth term of the sequence 4, -24, 144, ....

nadezda [96]

Answer:

Tn = 4(-6)^n-1

Step-by-step explanation:

Write an explicit formula for an, the nth term of the sequence 4, -24, 144, ....

The sequence is a geometric sequence

Tn = ar^n-1

a is the first term

a = 4

r = -24/4 =144/-24

r = -6

Substitute

Tn = 4(-6)^n-1

3 0

3 years ago

In Spring, Jack trimmed his tree 3 in. Shorter. In the summer he trimmed it 5 more inches. The tree is now 45 in. Tall. How tall

sergejj [24]

Answer: 53 inches

Step-by-step explanation:3+5=8

45+8= 53

7 0

3 years ago

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Carina says that to divide by 12, she will need to write 12 as the fraction and then divide. Is she correct? Explain your reason

Alika [10]

Answer:

I do not know

Step-by-step explanation:

I think so

6 0

2 years ago

Evaluate each value expression for the given value of x : 22-x/5 , x=20<br><br> HURY!!!!!!!!!!!

ozzi

Answer= 18

22-20/5
22-4
=18

5 0

3 years ago

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manuel deposits $10000 for 12 yr in an account paying 4% compounded annually.He then puts this total amount on deposit in anothe

Naddik [55]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$10000\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}
\\\\\\
A=10000\left(1+\frac{0.04}{1}\right)^{1\cdot 12}\implies A=1000(1.04)^{12}\\\\\\ A\approx 16010.32$

he then turns around and grabs that money and sticks it for another 9 years,

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
~~
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$16010.32\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\
t=years\to &9
\end{cases}
\\\\\\
A=16010.32\left(1+\frac{0.05}{2}\right)^{2\cdot 9}\implies A=16010.32(1.025)^{18}
\\\\\\
A\approx 24970.64$

add both amounts, and that's how much is for the whole 21 years.

6 0

4 years ago