The sum of two consecutive odd integers is at most 123. find the pair with the greatest sum
two consecutive odd integers
2x+1,2x+3
The sum of two consecutive odd integers is at most 123
2x+1+2x+3≤123
Solve for x
2x+1+2x+3≤123
4x+4≤123
4x+4-4≤123-4
4x≤119
4/4x≤119/4
x≤119/4
x≤29.25
Substitute any numbers into x that are equal to 29 or less that are consecutive odd integers.
2x+1,2x+3
2 (29)+1,2 (29)+3
58+1,58+3
59,61
Check: 59+61=120
The pair of consecutive odd integers that have a sum of at most 123 are 59 and 61.
I believe if I have done this right the answer will be 1352
<span>6cm - 900000cm multiplica cruzado ⇒ 6x = 900000 ⇒ x = 150000cm
1cm - x
1cm - 150000cm multiplica cruzado -> d = 600000cm = 6km 4cm - d
</span>LETRA A
Answer:
0.5×2/2=1/2 is the required fraction.
Answer:
Correct answer: C. -20
Step-by-step explanation:
If (x-3) is a polynomial factor it means that the polynomial value at point 3 is zero.
H(3) = 3 · 3³ - 2 · 3² + 3k - 3 = 0 ⇒ 81 - 18 + 3k - 3 = 0 ⇒ 3k + 60 = 0
3k = - 60 ⇒ k = - 60/ 3 = - 20
k = - 20
God is with you!!!
