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4 years ago

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disk mass 2kg sliding on smooth surface velocit 5m/s when it strikes 4kg disk b sliding forward at 2m/s. direct cnetral impact C

oefficient of restitution is 0.4. compute velocities after

1 answer:

jonny [76]4 years ago

8 0

Explanation:

Below is an attachment containing the solution.

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Determine the required height h of the roller coaster so that when it is essentially at rest at the crest of the hill A it will

Dmitriy789 [7]

Answer:

a) 39.37 m

b) 26.25 m

Explanation:

Given

speed of the roller coaster, v = 100 km/h = 100 * (1000/3600) m/s = 27.78 m/s

Using the law of conservation of energy.

Potential Energy = Kinetic Energy

mgh = 1/2mv²

gh = 1/2v²

h = v²/2g

h = 27.78² / 2 * 9.8

h = 771.7284 / 19.6

h = 39.37 m

Also,

kmg - mg = mv²/p

kg - g = v²/p

p = v²/g(k - 1)

p = 27.78² / 9.8(4 - 1)

p = 771.7284 / 29.4

p = 26.25 m

Therefore, the height of the roller coaster is 39.37 m and the radius of curvature required is 26.25 m

8 0

3 years ago

A hovering mosquito is hit by a raindrop that is 50 times as massive and falling at 8.9 m/s , a typical raindrop speed. How fast

Ivahew [28]

Answer:

v = 8.72 m/s

Explanation:

To find the speed of the raindrop joint to the mosquito, you take into account the momentum conservation law for an inelastic collision. Before the collision the total momentum of raindrop and mosquito must be equal to the total momentum of both raindrop and mosquito after the collision.

$m_1v_1+m_2v_2=(m_1+m_2)v$ (1)

v1: speed of the mosquito before the collision= 0 m/s (it is at rest)

v2: speed of the raindrop before the collision = 8.9 m/s

m1: mass of the mosquito

m2: mass of the raindrop = 50m1 (50 time more massive that the mosquito)

v: speed of both raindrop and mosquito after the collision

You solve the equation (1) for v and replace the values of the rest of the parameters:

$v=\frac{m_1v_1+m_2v_2}{m_1+m_2}=\frac{m_1v_1+50m_1v_2}{m_1+50m_1}\\\\v=\frac{0m/s+50(8.9m/s)}{51}=8.72\frac{m}{s}$

hence, after the inelastic collision the speed of the raindrop andmosquito is 8.72 m/s

3 0

3 years ago

A father demonstrates projectile motion to his children by placing a pea on his fork's handle and rapidly depressing the curved

MariettaO [177]

Answer:

4.17 m/s

Explanation:

To solve this problem, let's start by analyzing the vertical motion of the pea.

The initial vertical velocity of the pea is

$u_y = u sin \theta = (7.39)(sin 69.0^{\circ})=6.90 m/s$

Now we can solve the problem by applying the suvat equation:

$v_y^2-u_y^2=2as$

where

$v_y$ is the vertical velocity when the pea hits the ceiling

$a=g=-9.8 m/s^2$ is the acceleration of gravity

s = 1.90 is the distance from the ceiling

Solving for $v_y$ ,

$v_y = \sqrt{u_y^2+2as}=\sqrt{(6.90)^2+2(-9.8)(1.90)}=3.22 m/s$

Instead, the horizontal velocity remains constant during the whole motion, and it is given by

$v_x = u cos \theta = (7.39)(cos 69.0^{\circ})=2.65 m/s$

Therefore, the speed of the pea when it hits the ceiling is

$v=\sqrt{v_x^2+v_y^2}=\sqrt{2.65^2+3.22^2}=4.17 m/s$

5 0

3 years ago

_______ says the universe began as a point and expanded.

Dominik [7]

C Evolution says the universe began as a point and expanded

4 0

3 years ago

Find the cp of an article which is sold for rupees 4048 , thereby , making a profit of 15 percent

mestny [16]

Answer:

4048 = 115x/100.

Explanation:

Profit P = (15/100) X x.

P= 15x/100.

15x/100 = 4048- x.

4048 = 15x/100 + x.

4048 = 115x/100.

6 0

3 years ago