Two long, straight parallel wires 8.2 cm apart carry currents of equal magnitude I. The parallel wires repel each other with a f
orce per unit length of 3.2 nN/m. The permeability of free space is 4 π × 10−7 T · m/A. Find I. Answer in units of mA.
1 answer:
Answer:
36.22 mA
Explanation:
i1 = I , i2 = I, d = 8.2 cm = 0.082 m
Force per unit length = 3.2 nN/m = 3.2 x 10^-9 N/m
μo = 4 π × 10^-7 Tm/A
The formula for the force per unit length between the two wires is given by
F = μo / 4π x (2 i1 x i2) / d
3.2 x 10^-9 = 10^-7 x 2 x I^2 / 0.082
I = 0.0362 A = 36.22 mA
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