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Jlenok [28]
2 years ago
5

How is a snowboarder able to soar through the air?

Physics
2 answers:
Readme [11.4K]2 years ago
5 0
Athletes flex and extend different muscles at takeoff. This creates angular momentum, or momentum of rotation. It allows a snowboarder to flip and spin in the air. The force of drag comes from air pushing against a snowboarder.
Step2247 [10]2 years ago
3 0

Answer: momentum

Explanation:

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Which one of the following is not a derived quantity a)speed b)velocity c)time d)force​
qaws [65]

Answer:

c) time

Explanation:

time is a fundamental quantity from which other quantities are derived

5 0
3 years ago
Why did the rest of the bulbs go out if you break the connection at one bulb?
evablogger [386]

electricity can't flow anymore if the wire isnt connected at the beginning

4 0
3 years ago
An object originally at rest, is accelerated uniformly along a straight line to a speed of 8m/s in 2s. What is the acceleration
Anna11 [10]

Answer:

4m/s²

Explanation:

Initial velocity (u) = 0 m/s

Final velocity (v) = 8 m/s

Time taken (t) = 2 sec

Acceleration (a) = ?

We know

a  =  \frac{v - u}{t}  \\  =  \frac{8 - 0}{2} \\  =  \frac{8}{2}  \\  = 4 \: m |s ^{2}

Hope it will help :)

3 0
3 years ago
2. Two projectiles thrown from the same point at angles 0,=60° and 02=30° with the horizontal,
Liono4ka [1.6K]

Answer:

The answer is below

Explanation:

The maximum height (h) of a projectile with an initial velocity of u, acceleration due to gravity g and at an angle θ with the horizontal is given as:

h=\frac{u^2sin^2\theta}{2g}

Given that the two projectile has the same height.

For\ the\ first\ projectile\ with\ an\ angle\ \60^0 \ with\ the\ horizontal\ and initial\ velocity\ u_1:\\\\h=\frac{u_1^2sin^260}{2g} =\frac{0.75u_1^2}{2g} \\\\For\ the\ second\ projectile\ with\ an\ angle\ \30 \ with\ the\ horizontal\ and initial\ velocity\ u_2:\\\\h=\frac{u_2^2sin^230}{2g} =\frac{0.25u_2^2}{2g}\\\\\frac{0.25u_2^2}{2g}=\frac{0.75u_1^2}{2g}\\\\0.25u_2^2=0.75u_1^2\\\\\frac{u_1^2}{u_2^2} =\frac{0.25}{0.75} \\\\\frac{u_1^2}{u_2^2}=\frac{1}{3} \\\\\frac{u_1}{u_2}=\sqrt\frac{1}{3}

8 0
3 years ago
Does the shape of molecule affect the chemical bond?​
just olya [345]

There is a sharp distinction between ionic and covalent bonds when the geometric arrangements of atoms in compounds are considered. In essence, ionic bonding is nondirectional, whereas covalent bonding is directional.

7 0
3 years ago
Read 2 more answers
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