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Vlad [161]
3 years ago
15

Absolute Zero is when energy / molecules stop moving.

Physics
1 answer:
denis-greek [22]3 years ago
3 0

Answer:

yes

Explanation:

When all of the molecules (or atoms) in a system stop moving completely, that's as cold as they can get

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What is a gas-like mixture that is made of charged particles?<br><br> (Physical Science)
Juli2301 [7.4K]

Answer:

I believe the answer is Plasma

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3 years ago
What do you mean by population size explain​
torisob [31]
Population size is the actual number of individuals in a population. Population density is a measurement of population size per unit area, i.e., population size divided by total land area. Abundance refers to the relative representation of a species in a particular ecosystem.
8 0
3 years ago
a wave travels at a speed of 793 m/s and has a wavelength of 2.3 meters. calculate the frequency of the wave​
Savatey [412]

Answer:

344.8 Hz

Explanation:

The frequency of a wave is given by:

f=\frac{v}{\lambda}

where

v is the speed of the wave

\lambda is its wavelength

Here we have

v = 793 m/s

\lambda=2.3 m

Substituting into the equation, we find

f=\frac{793 m/s}{2.3 m}=344.8 Hz

4 0
3 years ago
Suppose you take a piece of hard wax from an unlit candle. After you roll the wax between your fingers for a while, it becomes s
romanna [79]

Answer:

An amorphous solid does not have a definite melting point; instead, it melts gradually over a range of temperatures, because the bonds do not break all at once. This means an amorphous solid will melt into a soft, malleable state (think candle wax or molten glass) before turning completely into a liquid.

Explanation:

Hope this helps

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5 0
3 years ago
A thin rod of length L and total charge Q has the nonuniform linear charge distribution λ(x)=λ0x/L, where x is measured from the
marissa [1.9K]

Answer:

Explanation:

λ(x) = λo x/ L

(a) The total charge is Q.

Q=\int_{0}^{L}dq

Q=\int_{0}^{L}\frac{\lambda _{0}x}{L}dx

Q=\frac{\lambda _{0}}{2L}\left ( x^{2} \right )_{0}^{L}

Q=\frac{\lambda _{0}}{2L}

λo = 2Q/L

(b)

Let at a distance x from the origin the charge is dq.

so, dq = (2Q/L) x/ L dx

dq=\frac{2Qx}{L^{2}}dx

The potential due to this small charge at a distance d to the left of origin

dV = \frac{KdQ}{d+x}

\int_{0}^{V}dV = \frac{2KQ}{L^{2}}\int_{0}^{L}\frac{xdx}{d+x}

V = \frac{2KQ}{L^{2}}\int_{0}^{L}\left ( 1- \frac{d}{d+x}\right )dx

V = \frac{2KQ}{L^{2}}\times \left ( x-dln(d+x) \right )\int_{0}^{L}

V = \frac{2KQ}{L^{2}}\times \left ( L-dln(d+L)-0+dlnd \right )

V = \frac{Q}{4\pi \epsilon _{0}L^{2}}\times \left ( L+d\times ln\left (\frac{d}{d+L}  \right )\right )

4 0
3 years ago
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